JQuery getJson 成功函数在单击按钮时触发
JQuery getJson success function is firing on button click
我无法触发 getjson 成功事件。当我在 $(document).ready 上调用 $.getJSON 时,它工作正常,当我将相同的代码放在单击按钮下时,它不起作用。
工作正常(在 $(document).ready 下)
<html>
<head>
<title>API Logger</title>
<script type="text/javascript" src="http://code.jquery.com/jquery-2.1.4.min.js" ></script>
<script>
"use strict";
$(document).ready(function(){
var flickerAPI = "http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";
$.getJSON( flickerAPI,
{
tags: "mount everest",
tagmode: "any",
format: "json"
},
function(data)
{
alert("success");
});
});
</script>
</head>
<body>
<form>
<button id="btn1" >Execute</button>
</form>
</body>
不工作(在 $('#btn1').on('click', function()
<html>
<head>
<title>API Logger</title>
<script type="text/javascript" src="http://code.jquery.com/jquery-2.1.4.min.js" ></script>
<script>
"use strict";
$(document).ready(function(){
$('#btn1').on('click', function() {
var flickerAPI = "http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";
$.getJSON( flickerAPI,
{
tags: "mount everest",
tagmode: "any",
format: "json"
},
function(data)
{
alert("success");
});
});
});
</script>
</head>
<body>
<form>
<button id="btn1" >Execute</button>
</form>
</body>
它不起作用,因为您将按钮放在表单中
<form>
<button id="btn1" >Execute</button>
</form>
它会在您每次单击时提交,换句话说,它会重新加载页面。
只需在表单中定义按钮类型。
像这样尝试
<form>
<button type="button" id="btn1" >Execute</button>
</form>
或者直接在点击事件中添加return false
$(document).ready(function () {
$('#btn1').on('click', function () {
var flickerAPI = "http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";
$.getJSON(flickerAPI, {
tags: "mount everest",
tagmode: "any",
format: "json"
}, function (data) {
alert("success");
});
return false;
});
});
我无法触发 getjson 成功事件。当我在 $(document).ready 上调用 $.getJSON 时,它工作正常,当我将相同的代码放在单击按钮下时,它不起作用。
工作正常(在 $(document).ready 下)
<html>
<head>
<title>API Logger</title>
<script type="text/javascript" src="http://code.jquery.com/jquery-2.1.4.min.js" ></script>
<script>
"use strict";
$(document).ready(function(){
var flickerAPI = "http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";
$.getJSON( flickerAPI,
{
tags: "mount everest",
tagmode: "any",
format: "json"
},
function(data)
{
alert("success");
});
});
</script>
</head>
<body>
<form>
<button id="btn1" >Execute</button>
</form>
</body>
不工作(在 $('#btn1').on('click', function()
<html>
<head>
<title>API Logger</title>
<script type="text/javascript" src="http://code.jquery.com/jquery-2.1.4.min.js" ></script>
<script>
"use strict";
$(document).ready(function(){
$('#btn1').on('click', function() {
var flickerAPI = "http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";
$.getJSON( flickerAPI,
{
tags: "mount everest",
tagmode: "any",
format: "json"
},
function(data)
{
alert("success");
});
});
});
</script>
</head>
<body>
<form>
<button id="btn1" >Execute</button>
</form>
</body>
它不起作用,因为您将按钮放在表单中
<form>
<button id="btn1" >Execute</button>
</form>
它会在您每次单击时提交,换句话说,它会重新加载页面。
只需在表单中定义按钮类型。
像这样尝试
<form>
<button type="button" id="btn1" >Execute</button>
</form>
或者直接在点击事件中添加return false
$(document).ready(function () {
$('#btn1').on('click', function () {
var flickerAPI = "http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";
$.getJSON(flickerAPI, {
tags: "mount everest",
tagmode: "any",
format: "json"
}, function (data) {
alert("success");
});
return false;
});
});