从用户位置查找数组中最近的经度和纬度 - iOS Swift

Question

在发布的问题 here 中，用户问：

I have an array full of longitudes and latitudes. I have two double variables with my users location. I'd like to test the distance between my user's locations against my array to see which location is the closest. How do I do this?

This will get the distance between 2 location but stuggeling to understand how I'd test it against an array of locations.

作为响应，他得到了以下代码：

NSArray *locations = //your array of CLLocation objects
CLLocation *currentLocation = //current device Location

CLLocation *closestLocation;
CLLocationDistance smallestDistance = DBL_MAX; // set the max value

for (CLLocation *location in locations) {
    CLLocationDistance distance = [currentLocation  distanceFromLocation:location];

    if (distance < smallestDistance) {
        smallestDistance = distance;
        closestLocation = location;
    }
}
NSLog(@"smallestDistance = %f", smallestDistance);

我正在处理的应用程序中存在完全相同的问题，我认为这段代码可以完美运行。但是，我正在使用 Swift，此代码位于 Objective-C.

我唯一的问题是：它在 Swift 中应该如何显示？

感谢您的帮助。我对这一切都是新手，在 Swift 中看到这段代码可能是一个很大的进步。

Answer 1

var closestLocation: CLLocation?
var smallestDistance: CLLocationDistance?

for location in locations {
  let distance = currentLocation.distanceFromLocation(location)
  if smallestDistance == nil || distance < smallestDistance {
    closestLocation = location
    smallestDistance = distance
  }
}

print("smallestDistance = \(smallestDistance)")

或作为函数：

func locationInLocations(locations: [CLLocation], closestToLocation location: CLLocation) -> CLLocation? {
  if locations.count == 0 {
    return nil
  }

  var closestLocation: CLLocation?
  var smallestDistance: CLLocationDistance?

  for location in locations {
    let distance = location.distanceFromLocation(location)
    if smallestDistance == nil || distance < smallestDistance {
      closestLocation = location
      smallestDistance = distance
    }
  }

  print("closestLocation: \(closestLocation), distance: \(smallestDistance)")
  return closestLocation
}

Answer 2

为了 Swift 3 我创建了这段 "functional" 代码：

let coord1 = CLLocation(latitude: 52.12345, longitude: 13.54321)
let coord2 = CLLocation(latitude: 52.45678, longitude: 13.98765)
let coord3 = CLLocation(latitude: 53.45678, longitude: 13.54455)

let coordinates = [coord1, coord2, coord3]

let userLocation = CLLocation(latitude: 52.23678, longitude: 13.55555)

let closest = coordinates.min(by: 
{ [=10=].distance(from: userLocation) < .distance(from: userLocation) })

Answer 3

    func closestLoc(userLocation:CLLocation){
    var distances = [CLLocationDistance]()
    for location in locations{
        let coord = CLLocation(latitude: location.latitude!, longitude: location.longitude!)
        distances.append(coord.distance(from: userLocation))
        print("distance = \(coord.distance(from: userLocation))")
    }

    let closest = distances.min()//shortest distance
    let position = distances.index(of: closest!)//index of shortest distance
    print("closest = \(closest!), index = \(position)")
}

从用户位置查找数组中最近的经度和纬度 - iOS Swift

Find closest longitude and latitude in array from user location - iOS Swift

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