格式化 java 中的字符串以完美匹配

Formatting a string in java to match up perfectly

所以我想知道是否有人可以帮助我格式化这个...

这是目前的样子:

这就是我需要的样子(没有 ...):

这是我目前的代码:

    System.out.format( "%n$------------------------------------$");
    System.out.format( "%nWITHHOLDING FOR EACH EMPLOYEE%n%n" );
    System.out.format( "First Name        Last Name        Hourly Rate        Weekly Pay        Withholding Amount%n%n" );
    for( int i = 0; i < employeeNum; i++ ) {
        System.out.format( "%-10s %-10s %-10.3f %-10.3f %-10.3f%n", employeeFirstName[i], employeeLastName[i], 
                employeeHourlyPay[i], weeklyPay[i], withholdingAmt[i] );
    }
    System.out.format( "%nEND OF REPORT%n" );
    System.out.format( "$------------------------------------$");

感谢您的帮助!

使用它来截断长字符串:

static String truncto( String s, int max ){
    return s.length() > max ? s.substring(0,max) : s;
}

您可以使用它来获得对齐的输出

System.out.format( "First Name        Last Name        Hourly Rate        Weekly Pay        Withholding Amount%n%n" );
System.out.format( "%-17s %-16s %-18.3f %-17.0f %-17.0f%n", 
           truncto("John-Bulwer-Lytton",17),
           truncto("Smith",16),
           123.45, 200.0, 100.0 );

使用您的数组元素代替我用于测试的文字。

您肯定可以为 header 打印两行。

这里我已经做到了,只是也使用header中的对齐:

System.out.print( "%n$------------------------------------$");
System.out.printf( "%nWITHHOLDING FOR EACH EMPLOYEE%n%n" );
System.out.printf("%-12s  %-12s  %-12s  %-12s  %-12s \n\n", "First Name", "Last Name", "Hourly Rate", "Weekly Pay", "Withholding Amount");

for( int i = 0; i < employeeNum; i++ ) {
    System.out.printf( "%-12s  %-12s  %-12.3f  %-12.3f  %-12.3f \n", employeeFirstName[i], employeeLastName[i], 
            employeeHourlyPay[i], weeklyPay[i], withholdingAmt[i] );
}
System.out.printf( "%nEND OF REPORT%n" );
System.out.print( "$------------------------------------$");

这是输出:

...
First Name    Last Name     Hourly Rate   Weekly Pay    Withholding Amount 

Brett         Lawless       25.500        1020.000      204.000      
....