Python zipfile 不释放 zip 文件

Question

我正在尝试在 windows 8.1 和 python 2.7.9 上使用 zipfile 库。

我只想在 zipfile.open() 之后删除 library.zip 但是 os.remove() 抛出 "WindowsError [Error 32]" 并且 zipfile 似乎没有释放 zip 文件带块。

WindowsError 32 表示 "The process cannot access the file because it is being used by another process."

那么，我该如何删除这个 library.zip 文件？

代码：

import os
import zipfile as z

dirs = os.listdir('build/')
bSystemStr = dirs[0]

print("[-] Merging library.zip...")
with z.ZipFile('build/' + bSystemStr + '/library.zip', 'a') as z1:
    with z.ZipFile('build_temp/' + bSystemStr + '/library.zip', 'r') as z2:
        for t in ((n, z2.open(n)) for n in z2.namelist()):
            try:
                z1.writestr(t[0], t[1].read())
            except:
                pass

print("[-] Cleaning temporary files...")
os.remove('build_temp/' + bSystemStr + '/library.zip')

错误：

[-]Merging library.zip...
...
build.py:74: UserWarning: Duplicate name: 'xml/sax/_exceptions.pyc'
  z1.writestr(t[0], t[1].read())
build.py:74: UserWarning: Duplicate name: 'xml/sax/expatreader.pyc'
  z1.writestr(t[0], t[1].read())
build.py:74: UserWarning: Duplicate name: 'xml/sax/handler.pyc'
  z1.writestr(t[0], t[1].read())
build.py:74: UserWarning: Duplicate name: 'xml/sax/saxutils.pyc'
  z1.writestr(t[0], t[1].read())
build.py:74: UserWarning: Duplicate name: 'xml/sax/xmlreader.pyc'
  z1.writestr(t[0], t[1].read())
build.py:74: UserWarning: Duplicate name: 'xmllib.pyc'
  z1.writestr(t[0], t[1].read())
build.py:74: UserWarning: Duplicate name: 'xmlrpclib.pyc'
  z1.writestr(t[0], t[1].read())
build.py:74: UserWarning: Duplicate name: 'zipfile.pyc'
  z1.writestr(t[0], t[1].read())
[-] Cleaning temporary files...
Traceback (most recent call last):
  File "build.py", line 79, in <module>
    os.remove('build_temp/' + bSystemStr + '/library.zip')
WindowsError: [Error 32] : 'build_temp/exe.win32-2.7/library.zip'

Answer 1

我认为您必须按照 python 文档 https://docs.python.org/2/library/zipfile.html#zipfile.ZipFile.close

中所述，在删除或退出程序之前关闭您的存档

因此运行 z1.close() 和 z2.close() 在删除存档之前

您的代码必须如下所示：

import os
import zipfile as z

dirs = os.listdir('build/')
bSystemStr = dirs[0]

print("[-] Merging library.zip...")
with z.ZipFile('build/' + bSystemStr + '/library.zip', 'a') as z1:
    with z.ZipFile('build_temp/' + bSystemStr + '/library.zip', 'r') as z2:
        for t in ((n, z2.open(n)) for n in z2.namelist()):
            try:
                z1.writestr(t[0], t[1].read())
            except:
                pass

         z2.close()

     z1.close()


print("[-] Cleaning temporary files...")
os.remove('build_temp/' + bSystemStr + '/library.zip')

如果我错了，请纠正我。

Python zipfile 不释放 zip 文件

Python zipfile dosen't release zip file

python

windows

python-2.7

windows-8.1

python-zipfile