你能从调用者那里得到 __FUNCTION__ 吗?
Can you get __FUNCTION__ from the caller?
示例:
@noreturn func setOnlyPropertyGetterError(__function__: String) {
fatalError("\(__function__) is set-only")
}
var property: Property {
get {setOnlyPropertyGetterError(__FUNCTION__)}
set {//useful work}
}
我们可以避免必须通过 __FUNCTION__
吗?
我认为这就是你想要实现的:
@noreturn func writeOnlyProperty(propertyName: String = __FUNCTION__) {
fatalError("Property \(propertyName) is write-only")
}
class Foo {
var blackHole: Int {
get { writeOnlyProperty() }
set { print("Consuming value \(newValue)") }
}
}
let foo = Foo()
foo.blackHole = 1 // Prints "Consuming value 1"
let bar = foo.blackHole // Produces fatal error "Property blackHole is write-only"
示例:
@noreturn func setOnlyPropertyGetterError(__function__: String) {
fatalError("\(__function__) is set-only")
}
var property: Property {
get {setOnlyPropertyGetterError(__FUNCTION__)}
set {//useful work}
}
我们可以避免必须通过 __FUNCTION__
吗?
我认为这就是你想要实现的:
@noreturn func writeOnlyProperty(propertyName: String = __FUNCTION__) {
fatalError("Property \(propertyName) is write-only")
}
class Foo {
var blackHole: Int {
get { writeOnlyProperty() }
set { print("Consuming value \(newValue)") }
}
}
let foo = Foo()
foo.blackHole = 1 // Prints "Consuming value 1"
let bar = foo.blackHole // Produces fatal error "Property blackHole is write-only"