如何将参数传递给 Java 线程?

How can I pass a parameters to a Java Thread?

我的程序无法运行,我该如何改进我的示例?

这段代码是错误的。 Eclipse 说 Cannot instantiate the type Synchro 行:Runnable threadTask = new Synchro(param1, param2);

button.addActionListener(new ActionListener() {
    @Override
    public void actionPerformed(ActionEvent e) {
        synchronizuj.setEnabled(false);
        String param1 = main_catalog.getText();
        String param2 = copy_catalog.getText();
        Runnable threadTask = new Synchro(param1, param2);
        Thread newThread = new Thread (threadTask);
        newThread.start();
    }
}); 

和class Synchro 在另一个文件中:(此代码适用于 Eclipse)

public abstract class Synchro implements Runnable { 
    private String argument1;
    private String argument2;

    public void run(String argument1, String argument2) {
        this.argument1 = argument1;
        this.argument2 = argument2;
        sleepThread();
    }

我觉得你的 Synchro class 应该是这样的。

public class Synchro implements Runnable {
    private String argument1;
    private String argument2;

    // the arguments pass by constructor
    public Synchro(String argument1, String argument2) {
        this.argument1 = argument1;
        this.argument2 = argument2;
    }

    // you have to override run method, when you implement Runnable interface
    @Override
    public void run() {
        // your code
    }
}

这是在 Java8 中工作的另一种方式:

button.addActionListener(new ActionListener() {
    @Override
    public void actionPerformed(ActionEvent e) {
        synchronizuj.setEnabled(false);
        final String param1 = main_catalog.getText();
        final String param2 = copy_catalog.getText();
        Thread newThread = new Thread (() -> {
            ...code to be executed in the thread goes here.
               It can refer to param1 and param2,
               but it can not change them...

        });
        newThread.start();
    }
});

new Thread(...) 的参数是一个 lambda 表达式--- 一种定义和实例化实现 功能接口(注:Runnable已经在Java8中re-defined作为功能接口。)