Unity3D代码重复太多
Unity3D Code repeats too much
我正在努力做到,如果你有足够的金子,那么你就需要石头,如果你有足够的石头,那么你就需要足够的金子,但如果你两者都有,那么你可以 "Upgrade"。但如果你两者都得到了,那么它又回到了你需要金币的问题。
void Update()
{
if(enoughgold == true & enoughrocks == true)
{
Upgrade.text = "Upgrade to 2014!";
}
if(sellrocks.gold > 9999)
{
enoughgold = true;
}
else
{
enoughgold = false;
}
if(click.rock > 2999)
{
enoughrocks = true;
}
else
{
enoughrocks = false;
}
if(enoughgold == true)
{
Upgrade.text = "You need 3,000 Rocks!";
}
else
{
Upgrade.text = "You need 10,000 Gold!";
}
if (enoughrocks == true)
{
Upgrade.text = "You need 10,000 Gold!";
}
else
{
Upgrade.text = "You need 3,000 Rocks!";
}
}
这样的事情怎么样?你先看看用户是否有足够的金币和石头,然后再做检查。
我已将 if (enoughgold == true)
简化为 if (enoughgold)
,因为 == true
是多余的。
void Update()
{
enoughgold = sellrocks.gold > 9999;
enoughrocks = click.rock > 2999;
if (enoughgold && enoughrocks)
Upgrade.text = "Upgrade to 2014!";
else if (enoughgold && !enoughrocks)
Upgrade.text = "You need 3,000 Rocks!";
else if (!enoughgold && enoughrocks)
Upgrade.text = "You need 10,000 Gold!";
else if (!enoughgold && !enoughrocks)
Upgrade.text = "You need 10,000 Gold and 3,000 Rocks!";
}
您还可以创建一个枚举来处理所有 4 种可能性:如果用户只有足够的石头,如果用户只有足够的金子,如果用户两者都足够,如果用户没有足够的任何。
我正在努力做到,如果你有足够的金子,那么你就需要石头,如果你有足够的石头,那么你就需要足够的金子,但如果你两者都有,那么你可以 "Upgrade"。但如果你两者都得到了,那么它又回到了你需要金币的问题。
void Update()
{
if(enoughgold == true & enoughrocks == true)
{
Upgrade.text = "Upgrade to 2014!";
}
if(sellrocks.gold > 9999)
{
enoughgold = true;
}
else
{
enoughgold = false;
}
if(click.rock > 2999)
{
enoughrocks = true;
}
else
{
enoughrocks = false;
}
if(enoughgold == true)
{
Upgrade.text = "You need 3,000 Rocks!";
}
else
{
Upgrade.text = "You need 10,000 Gold!";
}
if (enoughrocks == true)
{
Upgrade.text = "You need 10,000 Gold!";
}
else
{
Upgrade.text = "You need 3,000 Rocks!";
}
}
这样的事情怎么样?你先看看用户是否有足够的金币和石头,然后再做检查。
我已将 if (enoughgold == true)
简化为 if (enoughgold)
,因为 == true
是多余的。
void Update()
{
enoughgold = sellrocks.gold > 9999;
enoughrocks = click.rock > 2999;
if (enoughgold && enoughrocks)
Upgrade.text = "Upgrade to 2014!";
else if (enoughgold && !enoughrocks)
Upgrade.text = "You need 3,000 Rocks!";
else if (!enoughgold && enoughrocks)
Upgrade.text = "You need 10,000 Gold!";
else if (!enoughgold && !enoughrocks)
Upgrade.text = "You need 10,000 Gold and 3,000 Rocks!";
}
您还可以创建一个枚举来处理所有 4 种可能性:如果用户只有足够的石头,如果用户只有足够的金子,如果用户两者都足够,如果用户没有足够的任何。