计算字符串中的字符

Question

所以我试图计算 anhCrawler 和 return 带有和不带空格的字符数以及 "DEATH STAR" 和 return 它在报告中的位置。我也无法正确计算数字。请帮忙！

anhCrawler = """Episode IV, A NEW HOPE. It is a period of civil war. \
Rebel spaceships, striking from a hidden base, have won their first \
victory against the evil Galactic Empire. During the battle, Rebel \
spies managed to steal secret plans to the Empire's ultimate weapon, \
the DEATH STAR, an armored space station with enough power to destroy \
an entire planet. Pursued by the Empire's sinister agents, Princess Leia\
races home aboard her starship, custodian of the stolen plans that can \
save her people and restore freedom to the galaxy."""

theReport = """
This text contains {0} characters ({1} if you ignore spaces).
There are approximately {2} words in the text. The phrase
DEATH STAR occurs and starts at position {3}.
"""

def analyzeCrawler(thetext):
numchars = 0
nospacechars = 0
numspacechars = 0
anhCrawler = thetext
word = anhCrawler.split()
for char in word:
    numchars = word[numchars]
    if numchars == " ":
        numspacechars += 1
anhCrawler = re.split(" ", anhCrawler)
for char in anhCrawler:
    nospacechars += 1
numwords = len(anhCrawler)
pos = thetext.find("DEATH STAR")
char_len = len("DEATH STAR")
ds = thetext[261:271]
dspos = "[261:271]"

return theReport.format(numchars, nospacechars, numwords, dspos)
print analyzeCrawler(theReport)

Answer 1

你想多了。

字符串中的字符数 (returns 520):

len(anhCrawler)

字符串中非空白字符的数量（使用 split 因为使用 split 会自动删除空白，而 join 创建一个没有空白的字符串）（returns 434):

len(''.join(anhCrawler.split()))

寻找"DEATH STAR"的位置（returns 261）：

anhCrawler.find("DEATH STAR")

Answer 2

首先，您需要缩进函数内的代码。其次...您的代码可以简化为以下内容：

theReport = """
    This text contains {0} characters ({1} if you ignore spaces).
    There are approximately {2} words in the text. The phrase
    DEATH STAR is the {3}th word and starts at the {4}th character.
"""

def analyzeCrawler(thetext):

    numchars = len(anhCrawler)
    nospacechars = len(anhCrawler.replace(' ', ''))
    numwords = len(anhCrawler.split())

    word = 'DEATH STAR'
    wordPosition = anhCrawler.split().index(word)
    charPosition = anhCrawler.find(word)

    return theReport.format(
        numchars, nospacechars, numwords, wordPosition, charPosition
    )

我修改了最后两个 format 参数，因为我不清楚 dspos 的意思，尽管它可能很明显，但我没有看到。在任何情况下，我都包含了单词和字符位置。您可以确定您真正想要包括哪一个。

Answer 3

在这里，您有函数的简化版本：

import re

def analyzeCrawler2(thetext, text_to_search = "DEATH STAR"):

    numchars = len(anhCrawler)
    nospacechars = len(re.sub(r"\s+", "", anhCrawler))
    numwords   = len(anhCrawler.split())
    dspos      =  anhCrawler.find(text_to_search)

    return theReport.format(numchars, nospacechars, numwords, dspos)



print analyzeCrawler2(theReport)


This text contains 520 characters (434 if you ignore spaces).
There are approximately 87 words in the text. The phrase
DEATH STAR occurs and starts at position 261.

我认为技巧部分是从字符串中删除白色 spaces 并计算非 space 字符数。这可以简单地使用正则表达式来完成。休息应该是不言自明的。

计算字符串中的字符

Count characters in string

python

charactercount