如何获取 ListView 的值并将其保存在 EditText 或其他活动中的其他内容中

Question

有一个带输入框的activity，它用ListView调用第二个activity。 我需要从 ListView 中获取值，然后 return 将其输入到第一个 activity 的输入字段中。不能 return 一个值，但是 activity 切换没有错误。

MainActivity

edTAirportchoice1 = (EditText) findViewById(R.id.edText);
    edText.setOnClickListener(this);

public void onClick(View v) {
        Intent intent = new Intent(MainActivity.this, ListActivity.class);
        startActivityForResult(intent, 1);

 @Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (data == null) {
        return;

    } String name = getIntent().getStringExtra("name");
    edText.setText(name);
    }

}

ListActivity

list1 = (ListView) findViewById(R.id.list1);
    list1.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, s1));
    list1.setOnItemClickListener(new AdapterView.OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            Toast.makeText(getApplicationContext(), s1[position], Toast.LENGTH_LONG).show();
            Intent intent = new Intent(ListActivity.this, MainActivity.class));
            intent.putExtra("name", s1[position]);
            setResult(1,intent);        
            finish();

public void onClick(View v) {
    Intent intent = new Intent(ListActivity.this, MainActivity.class);
    intent.putExtra("name", edText.getText().toString()); //("name", list1.getOnItemClickListener().toString())- the same result
    startActivity(intent);

Answer 1

Intent intent = new Intent(); 
        intent.putExtra("name", selectedResult); 
        setResult(1, intent);

Answer 2

为此目的使用 Intent，

从 ListActivity 到 MainActivity

public void onClick(View v) {
    Intent intent = new Intent(ListActivity.this, MainActivity.class);
    intent.putExtra("name", list1.getOnItemClickListener().toString());
    startActivity(intent);
}

现在在 MainActivity 获取名称的这个值，

String name= getIntent().getStringExtra("name");

现在在 MainActivity 的文本视图中设置值，

txtView.setText(name);

Answer 3

在 2 个活动之间共享一些数据的正确方法是：

public static final int REQUEST_LIST = 1;

// Call this to show ListActivity
Intent intent = new Intent(MainActivity.this, ListActivity.class);
startActivityForResult(intent, REQUEST_LIST);

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (resultCode == RESULT_OK) {
        switch(requestCode) {
            case REQUEST_LIST:
               if (data == null) return;
               String name = getIntent().getStringExtra("name");
               edText.setText(name);
               break;

            default:
               break;
        }
    }
}

然后在ListActivity中你需要：

list1 = (ListView) findViewById(R.id.list1);
list1.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, s1));
list1.setOnItemClickListener(new AdapterView.OnItemClickListener() {

    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        Intent resultIntent = new Intent();
        resultIntent.putExtra("name", s1[position]);
        setResult(RESULT_OK, resultIntent);        
        finish();
});

如何获取 ListView 的值并将其保存在 EditText 或其他活动中的其他内容中

How to get the value of ListView and save it in the EditText or something else in another activitiy

android

listview

parcelable

android-intent

android-studio