C Error: comparison between pointer and integer [enabled by default]

Question

我正在尝试学习一些基本的 C 代码，以增强我的一般技能。我写了一个基本脚本，告诉我一个数字是大于还是小于 10：

#include <stdio.h>
#include <unistd.h>
#include <string.h>


int main()
{
   int number;

   printf("Enter an integer\n");

   scanf("%d",&number);

   printf("Integer entered by you is %d\n", number);

   if ( "%d" > 10)
      printf("%d is greater than 10.\n", number);
   else
      printf("%d is less than 10.\n", number);

   return 0;
}

然而，当我编译它时，我收到一条错误消息，指出我正在尝试比较指针和整数：

dave@dave-[laptop]:~/Code/C/Examples$ gcc 004----takeandif.c -o 004----takeandif
004----takeandif.c: In function ‘main’:
004----takeandif.c:16:14: warning: comparison between pointer and integer [enabled by default]
    if ( "%d" > 10)
              ^

当我运行它时，它说所有数字都小于 10:

dave@dave-[laptop]:~/Code/C/Examples$ ./004----takeandif
Enter an integer
2
Integer entered by you is 2
2 is greater than 10.

None 的其他答案适用于我的情况。我应该改变什么？

Answer 1

替换

if ( "%d" > 10)

有

if( number > 10 )

Answer 2

我很确定 %d 只是一个占位符，既然你想将 "number" 的值与 10 进行比较，你应该写 "if (number > 10)" 而不是 "if (" %d" > 10)"

C Error: comparison between pointer and integer [enabled by default]

C Error: comparison between pointer and integer [enabled by default]

c

compiler-errors

compilation

compiler-warnings

ubuntu-14.04