VB.net 读取文本文件并使用提取的特定单词填充组合框

Question

我有一个问题让我很头疼。我真的以为有人已经问过这个了，但是几天的阅读和测试都没有结果。

我有一个文本文件开头：

"Determining profile based on KDBG search...

     Suggested Profile(s) : WinXPSP2x86, WinXPSP3x86 (Instantiated with WinXPSP2x86)"

（两者之间的空行不是错误，'Suggested'之前的空格也不是错误）

我只需要阅读以 'Suggested...' 开头的行并提取以 'Win' 开头的每个唯一单词并用它们填充一个组合框。（即 'WinXPSP2x86' 和 'WinXPSP3x86'）

我知道我需要使用 'StreamReader' class 并且可能会继续使用 Regex，但是，作为初学者，目前我无法将它们连接在一起。

有人能帮忙吗？将不胜感激。

Answer 1

正如一些人已经建议的那样：

使用System.IO.File.ReadAllLines，如果文件不是太大
遍历行数组
对于每一行，使用 Split 方法在 space
检查每个单词的前三个字符

这可行，但当然需要一些错误检查等：

        Dim lines() As String = System.IO.File.ReadAllLines("c:\temp\example.txt")

        Dim lineWords() As String
        For Each line As String In lines
            lineWords = line.Split(New Char() {" "}, System.StringSplitOptions.RemoveEmptyEntries)

            For Each word As String In lineWords
                If word.Length > 3 Then
                    If word.Substring(0, 3).ToUpper = "WIN" Then
                        cmbWords.Items.Add(word)
                    End If
                End If                
            Next
        Next

Answer 2

Imports System.IO
Public Class Form1

Private Sub Form1_Load( sender As Object,  e As EventArgs) Handles MyBase.Load

    ' BASIC is case sensitive and e is parameter so we will start
    ' new variables with the letter f.

    ' Read all lines of file into string array F.
    Dim F As String() = File.ReadAllLines("H:\Projects021241\Input.txt")
    ' F() is a 0 based array.  Assign 3 line of file to G.
    Dim G As String = F(2)
    ' On line 3 of file find starting position of the word 'win' and assign to H.
    ' TODO:  If it is not found H will be -1 and we should quit.
    Dim H As Integer = G.IndexOf("Win")
    ' Assign everything beginning at 'win' on line 3 to variable I.
    Dim I As String = G.Substring(H)
    ' The value placed in delimiter will separate remaining values in I.
    ' Place C after ending quote to represent a single character as opposed to a string.
    Dim Delimiter As Char = ","C
    ' J array will contain values left in line 3.
    Dim J As String() = I.Split(Delimiter)

    ' Loop through J array removing anything in parenthesis.
    For L = J.GetLowerBound(0) to J.GetUpperBound(0)
        ' Get location of open parenthesis.
        Dim ParenBegin As Integer = J(L).IndexOf("(")
        ' If no open parenthesis found continue.
        If ParenBegin <> -1 then
            ' Open parenthesis found.  Find closing parenthesis location
            ' starting relative to first parenthesis.
            Dim Temp As String = J(L).Substring(ParenBegin+1)
            ' Get location of ending parenthesis.
            Dim ParenEnd As Integer = Temp.IndexOf(")")
            ' TODO:  Likely an exception will be thrown if no ending parenthesis.
            J(L) = J(L).Substring(0,ParenBegin) & J(L).Substring(ParenBegin + ParenEnd +2)
            ' Change to include text up to open parenthesis and after closing parenthesis.
        End If
    Next L

    ' UnwantedChars contains a list of characters that will be removed.
    Dim UnwantedChars As String = ",()"""
    ' Check each value in J() for presence of each unwanted character.
    For K As Integer = 0 to (UnwantedChars.Length-1)
        For L = J.GetLowerBound(0) To J.GetUpperBound(0)
            ' Declare M here so scope will be valid at loop statement.
            Dim M As Integer = 0
            Do
                ' Assign M the location of the unwanted character or -1 if not found.
                M= J(L).IndexOf(UnwantedChars.Substring(K,1))
                ' Was this unwanted character found in this value?
                If M<>-1 Then
                    ' Yes - where was it found in the value?
                    Select Case M
                        Case 0  ' Beginning of value
                            J(L) = J(L).Substring(1)
                        Case J(L).Length    ' End of value.
                            J(L) = J(L).Substring(0,(M-1))
                        Case Else   ' Somewhere in-between.
                            J(L) = J(L).Substring(0,M) & J(L).Substring(M+1)
                    End Select
                Else
                    ' No the unwanted character was not found in this value.
                End If
            Loop Until M=-1 ' Go see if there are more of this unwanted character in the value.
        Next L  ' Next value.
    Next K  ' Next unwanted character.

    ' Loop through all the values and trip spaces from beginning and end of each.
    For L As Integer = J.GetLowerBound(0) To J.GetUpperBound(0)
        J(L) = J(L).Trim
    Next L  

    ' Assign the J array to the combobox.
    ComboBox1.DataSource = J

End Sub

End Class

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