如何从 java 中的 bufferedreader 读取&运行多个变量？

Question

之前我有这两个变量 (a),(total) 在两个不同的 class 但我无法获得 class.

的属性

所以，

我试着把这两个代码放在一个单一的 class 但没有一个变量起作用 System.out.println("( "+file1.getName() +" )-" +" Total no of words=" + a +"Total repeated words counted:"+total);

两者都不工作：

我目前的样本输出：

(博客39.txt)-重复单词总数counted:4,总字数words:0

都没有

(博客39.txt)-重复单词总数counted:0,总字数words:82

我需要的输出是：

(博客39.txt)-重复单词总数counted:4,总字数words:82

当我运行时，"a" 或 "total" 都不起作用。（反之亦然）如果我更改代码（可变）顺序。

谁能告诉我应该如何获得两个变量输出？？ :) 我是 java

的初学者

下面是我的代码。

package ramki;
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FilenameFilter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
import org.apache.commons.io.FileUtils;
import org.apache.commons.io.IOUtils;

public class newrepeatedcount {
    public static void main(String[] args) {
        FilenameFilter filter = new FilenameFilter() {
            public boolean accept(File dir, String name) {
                return name.endsWith(".txt");
            }
        };
        File folder = new File("E:\testfolder\");
        File[] listOfFiles = folder.listFiles(filter);
        for (int i = 0; i < listOfFiles.length; i++) {
            File file1 = listOfFiles[i];

            BufferedReader ins = null;
            try {
                ins = new BufferedReader(
                        new InputStreamReader(new FileInputStream(file1)));
            } catch (FileNotFoundException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            String line = "", str = "";
            String st = null;
            try {
                st = IOUtils.toString(ins);
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            // split text to array of words
            String[] words = st.split("\s");
            // frequency array
            int[] fr = new int[words.length];
            // init frequency array
            for (int i1 = 0; i1 < fr.length; i1++)
                fr[i1] = -1;
            // count words frequency
            for (int i1 = 0; i1 < words.length; i1++) {
                for (int j = 0; j < words.length; j++) {
                    if (words[i1].equals(words[j])) {
                        fr[i1]++;
                    }
                }
            }
            // clean duplicates
            for (int i1 = 0; i1 < words.length; i1++) {
                for (int j = 0; j < words.length; j++) {
                    if (words[i1].equals(words[j])) {
                        if (i1 != j)
                            words[i1] = "";
                    }
                }
            }
            int a = 0;
            try {
                while ((line = ins.readLine()) != null) {
                    str += line + " ";
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
            StringTokenizer st1 = new StringTokenizer(str);
            while (st1.hasMoreTokens()) {
                String s = st1.nextToken();
                a++;
            }
            int total = 0;
            for (int i1 = 0; i1 < words.length; i1++) {
                if (words[i1] != "") {
                    // System.out.println(words[i1]+"="+fr[i1]);
                    total += fr[i1];
                }
            }
            System.out.println("( " + file1.getName() + " )-"
                    + "Total repeated words counted:" + total + ","
                    + "total no of words:" + a);
            // System.out.println("total no of words:"+a);
        }
    }
}

Answer 1

如果您读完一个流，您将无法继续阅读。由于您的代码在很多方面都没有优化，我可以建议一种快速而肮脏的方法来使您的代码正常工作。在重新计算 "a" 的值之前，只需初始化分配给变量 "ins" 的 BufferedReader。

...
try {
    ins = new BufferedReader ( new InputStreamReader(new FileInputStream(file1)));
    while ((line = ins.readLine()) != null) {
        str += line + " ";
    }
} catch (IOException e) {
    e.printStackTrace();
}
...

Answer 2

每当你有这样的数据处理时，Java8's StreamAPI很可能是最好的选择。

// get all the files under this folder
Files.walk(Paths.get("E:\testfolder\"))
        // keep all the files ending in .txt
        .filter(p -> p.toString().toLowerCase().endsWith(".txt"))
        .forEach(p -> {
            try {
                // process all the lines of the file.
                Map<String, Long> wordCount = Files.lines(p)
                        // break the lines into words
                        .flatMap(l -> Stream.of(l.split("\s")))
                        // collect the words and count them
                        .collect(Collectors.groupingBy(w -> w, Collectors.counting()));
                // find how many values are more than 1
                long wordDuplicates = wordCount.values().stream().filter(l -> l > 1).count();
                // get the sum of all the values.
                long totalWords = wordCount.values().stream().mapToLong(l -> l).sum();
                System.out.println(p + " has " + wordDuplicates + " duplicates and " + totalWords + " words");
            // catch the IOException at the end because you can't do anything more with the file if this happens.
            } catch (IOException e) {
                e.printStackTrace();
            }
        });

Answer 3

我不确定这是否是最佳解决方案，但这会给你一个集合或地图（在内部你可以转换它在你的文本中出现的次数。然后你可以根据你的要求使用它。

 import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.HashMap;
import java.util.Map;

 public class NewRepeatedCount  {

    public static void main(String... arg0)
    {
     BufferedReader br = null;
     Map<String, Integer> counterMap = new HashMap<String, Integer>();

        try {

            String sCurrentLine;

            br = new BufferedReader(new FileReader("C:\testing.txt"));

            while ((sCurrentLine = br.readLine()) != null) {
                String[] words = sCurrentLine.split("\s");
                for(String word : words)
                {
                    int count = 1;
                    if(counterMap.get(word) != null)
                    {
                        count = counterMap.get(word);
                        count++;
                        counterMap.put(word, count);
                    }else{
                        counterMap.put(word, count);
                    }

                }
            }
            System.out.println(counterMap.entrySet());

        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            try {
                if (br != null)br.close();
            } catch (IOException ex) {
                ex.printStackTrace();
            }
        }
    }
 }

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