无限循环在程序中无法正常工作
Infinite loop not working properly in program
此程序使用二维数组记录打开和保留rooms.The程序在开始时和每次更改数组后显示二维数组。索引值表示房间号,并针对开放房间显示。预订的房间显示预订房间的人的姓名。该程序将继续 运行 直到用户输入 "Q".
除了在主方法中执行一次循环后,程序停止了 运行,即使用户没有输入 "Q",对我来说一切似乎都很好。我也试过用 while(true) 来做,但它仍然没有用。我真的希望有人能帮助我。
public static void main (String [] args)
{
Scanner kb = new Scanner (in);
out.print("Enter row size: ");
int row = kb.nextInt();
out.print("Enter column size: ");
int col = kb.nextInt();
kb.nextLine();
String [][]rooms = roomInIt(row, col);
printMatrix(rooms);
String a="";
for(;;)
{
out.print("Would you like to reserve or release a room? Type Q to exit ");
a = kb.nextLine();
if (a.equalsIgnoreCase("reserve"))
{
out.print("How many rooms would you like to reserve? ");
int num = kb.nextInt();
reserveRooms(rooms, num);
}
else if (a.equalsIgnoreCase("release"))
{
out.print("How many rooms would you like to release? ");
int x = kb.nextInt();
releaseRooms(rooms, x);
}
else if (a.equalsIgnoreCase("Q"));
break;
}
}
public static void printMatrix(String[][]rooms)
{
for(int r=0; r<rooms.length; r++)
{
for (int c=0; c<rooms[r].length; c++)
out.print("["+r+","+c+"] "+rooms[r][c]+"\t");
out.println();
}
}
public static String[][] roomInIt(int row, int col)
{
String [][]rooms = new String [row][col];
for(int r=0; r<rooms.length; r++)
for (int c=0; c<rooms[r].length; c++)
rooms[r][c]="open";
return rooms;
}
public static void reserveRooms(String [][]room, int num)
{
Scanner kb = new Scanner(in);
for(int i=0; i<num; i++)
{
out.print("Enter name: ");
String name = kb.nextLine();
out.print("Enter the room number (row and column separated by a space) ");
int r=kb.nextInt();
int c=kb.nextInt();
kb.nextLine();
while (r<0 || r>room.length || c<0 || c>room[r].length || !room[r][c].equals("open"))
{
out.print("Invalid room number. Enter another room number (row and column separated by a space) ");
r=kb.nextInt();
c=kb.nextInt();
kb.nextLine();
}
room[r][c] = name;
}
printMatrix(room);
}
public static void releaseRooms(String [][]room, int x)
{
int r, c;
Scanner kb = new Scanner(in);
for(int i=0; i<x; i++)
{
out.print("Enter name: ");
String name = kb.nextLine();
out.print("Enter the room number (row and column separated by a space) ");
r=kb.nextInt();
c=kb.nextInt();
kb.nextLine();
while(r<0 || r>room.length || c<0 || c>room[r].length)
{
out.print("Invalid room number. Enter another room number (row and column separated by a space) ");
r=kb.nextInt();
c=kb.nextInt();
kb.nextLine();
}
room[r][c] = "open";
}
printMatrix(room);
}
去掉 else if (a.equalsIgnoreCase("Q"));
上的分号
;
结束语句,这意味着 break
总是完成,而不仅仅是在满足条件时。
去掉分号;
:
改变
else if (a.equalsIgnoreCase("Q"));
至
else if (a.equalsIgnoreCase("Q"))
而不是使用
for(;;)
{
out.print("Would you like to reserve or release a room? Type Q to exit ");
a = kb.nextLine();
if (a.equalsIgnoreCase("reserve"))
{
out.print("How many rooms would you like to reserve? ");
int num = kb.nextInt();
reserveRooms(rooms, num);
}
else if (a.equalsIgnoreCase("release"))
{
out.print("How many rooms would you like to release? ");
int x = kb.nextInt();
releaseRooms(rooms, x);
}
else if (a.equalsIgnoreCase("Q"));
break;
}
为什么不使用
while (!a.equalsIgnoreCase("Q"))
{
out.print("Would you like to reserve or release a room? Type Q to exit ");
a = kb.nextLine();
if (a.equalsIgnoreCase("reserve"))
{
out.print("How many rooms would you like to reserve? ");
int num = kb.nextInt();
reserveRooms(rooms, num);
}
else if (a.equalsIgnoreCase("release"))
{
out.print("How many rooms would you like to release? ");
int x = kb.nextInt();
releaseRooms(rooms, x);
}
else
{
//do nothing
}
}
此程序使用二维数组记录打开和保留rooms.The程序在开始时和每次更改数组后显示二维数组。索引值表示房间号,并针对开放房间显示。预订的房间显示预订房间的人的姓名。该程序将继续 运行 直到用户输入 "Q".
除了在主方法中执行一次循环后,程序停止了 运行,即使用户没有输入 "Q",对我来说一切似乎都很好。我也试过用 while(true) 来做,但它仍然没有用。我真的希望有人能帮助我。
public static void main (String [] args)
{
Scanner kb = new Scanner (in);
out.print("Enter row size: ");
int row = kb.nextInt();
out.print("Enter column size: ");
int col = kb.nextInt();
kb.nextLine();
String [][]rooms = roomInIt(row, col);
printMatrix(rooms);
String a="";
for(;;)
{
out.print("Would you like to reserve or release a room? Type Q to exit ");
a = kb.nextLine();
if (a.equalsIgnoreCase("reserve"))
{
out.print("How many rooms would you like to reserve? ");
int num = kb.nextInt();
reserveRooms(rooms, num);
}
else if (a.equalsIgnoreCase("release"))
{
out.print("How many rooms would you like to release? ");
int x = kb.nextInt();
releaseRooms(rooms, x);
}
else if (a.equalsIgnoreCase("Q"));
break;
}
}
public static void printMatrix(String[][]rooms)
{
for(int r=0; r<rooms.length; r++)
{
for (int c=0; c<rooms[r].length; c++)
out.print("["+r+","+c+"] "+rooms[r][c]+"\t");
out.println();
}
}
public static String[][] roomInIt(int row, int col)
{
String [][]rooms = new String [row][col];
for(int r=0; r<rooms.length; r++)
for (int c=0; c<rooms[r].length; c++)
rooms[r][c]="open";
return rooms;
}
public static void reserveRooms(String [][]room, int num)
{
Scanner kb = new Scanner(in);
for(int i=0; i<num; i++)
{
out.print("Enter name: ");
String name = kb.nextLine();
out.print("Enter the room number (row and column separated by a space) ");
int r=kb.nextInt();
int c=kb.nextInt();
kb.nextLine();
while (r<0 || r>room.length || c<0 || c>room[r].length || !room[r][c].equals("open"))
{
out.print("Invalid room number. Enter another room number (row and column separated by a space) ");
r=kb.nextInt();
c=kb.nextInt();
kb.nextLine();
}
room[r][c] = name;
}
printMatrix(room);
}
public static void releaseRooms(String [][]room, int x)
{
int r, c;
Scanner kb = new Scanner(in);
for(int i=0; i<x; i++)
{
out.print("Enter name: ");
String name = kb.nextLine();
out.print("Enter the room number (row and column separated by a space) ");
r=kb.nextInt();
c=kb.nextInt();
kb.nextLine();
while(r<0 || r>room.length || c<0 || c>room[r].length)
{
out.print("Invalid room number. Enter another room number (row and column separated by a space) ");
r=kb.nextInt();
c=kb.nextInt();
kb.nextLine();
}
room[r][c] = "open";
}
printMatrix(room);
}
去掉 else if (a.equalsIgnoreCase("Q"));
;
结束语句,这意味着 break
总是完成,而不仅仅是在满足条件时。
去掉分号;
:
改变
else if (a.equalsIgnoreCase("Q"));
至
else if (a.equalsIgnoreCase("Q"))
而不是使用
for(;;)
{
out.print("Would you like to reserve or release a room? Type Q to exit ");
a = kb.nextLine();
if (a.equalsIgnoreCase("reserve"))
{
out.print("How many rooms would you like to reserve? ");
int num = kb.nextInt();
reserveRooms(rooms, num);
}
else if (a.equalsIgnoreCase("release"))
{
out.print("How many rooms would you like to release? ");
int x = kb.nextInt();
releaseRooms(rooms, x);
}
else if (a.equalsIgnoreCase("Q"));
break;
}
为什么不使用
while (!a.equalsIgnoreCase("Q"))
{
out.print("Would you like to reserve or release a room? Type Q to exit ");
a = kb.nextLine();
if (a.equalsIgnoreCase("reserve"))
{
out.print("How many rooms would you like to reserve? ");
int num = kb.nextInt();
reserveRooms(rooms, num);
}
else if (a.equalsIgnoreCase("release"))
{
out.print("How many rooms would you like to release? ");
int x = kb.nextInt();
releaseRooms(rooms, x);
}
else
{
//do nothing
}
}