通过for循环动态更改unix中的变量名

Question

Today=$(date)
for i in {2..15}
do
 week_{$i}=$(date -d "$Today +$i week")
 echo ${week_2}
done

我在 BASH 的输出中没有得到任何值。

Answer 1

一种方式...

    Today=$(date)
    for i in {2..15} 
    do
        tmp=$(date -d "$Today +$i week")
        eval week_${i}=$tmp
        eval echo  $week_${i}
    done

第二种方式...

    Today=$(date)
    for i in {2..15} 
    do
        week_[$i]=$(date -d "$Today +$i week")
        echo ${week_[$i]}
    done

第三种方式...

    Today=$(date)
    for i in {2..15} 
    do
        eval echo ${week_${i}:=$(date -d "$Today +$i week")} > /dev/null
    done

    for i in {2..15} 
    do
        eval echo  $week_${i}
    done

通过for循环动态更改unix中的变量名

Dynamically changing variable name in unix through for loop

unix

for-loop

dynamic-variables