Symfony2.8。如何从 post 请求中获取数据
Symfony2.8. How to get data from post request
如何在我的控制器中接收来自 POST 请求的数据?
我不用树枝。
public function newAction(Request $request)
{
//when I use
$content = $request->getContent();
// as result I see "string" with need field and value. It's not json
// array
// value like
/*
string '------WebKitFormBoundaryI12ukQBs3HdmPjvh
Content-Disposition: form-data; name="title"
"valuefortitle"
------WebKitFormBoundaryI12ukQBs3HdmPjvh
Content-Disposition: form-data; name="name"
"supername"
------WebKitFormBoundaryI12ukQBs3HdmPjvh--
' (length=253)
*/
}
或者如何将 Post 数据序列化(转换)为 object 或数组
我使用 Postman 和 header "Content-Type: application/json" 发送请求。
你能告诉我如何保存文件(图片)吗?
您可以用于 POST 请求:
$request->request->get('data');
对于 GET 请求:
$request->query->get('data');
对于 FILE 查询:
$request->files.
并提出您的问题 How to save image?
,您必须创建 uploads -> excels
:
$dir = $this->get('kernel')->getRootDir() . '/../web/uploads/images/';
$name = uniqid() . '.jpeg';
foreach ($request->files as $uploadedFile) {
$uploadedFile->move($dir, $name);
}
$file = $this->get('kernel')->getRootDir() . "/../web/uploads/images/" . $name;
if (file_exists($file)) {
echo "Successfully saved";
}
转储请求中的所有数据以查找可能存在的问题:$request->request->all();
$request->request->get('content');
POST: $request->request->get('<propertyName>');
获取:$request->query->get('<propertyName>');
如何在我的控制器中接收来自 POST 请求的数据? 我不用树枝。
public function newAction(Request $request)
{
//when I use
$content = $request->getContent();
// as result I see "string" with need field and value. It's not json
// array
// value like
/*
string '------WebKitFormBoundaryI12ukQBs3HdmPjvh
Content-Disposition: form-data; name="title"
"valuefortitle"
------WebKitFormBoundaryI12ukQBs3HdmPjvh
Content-Disposition: form-data; name="name"
"supername"
------WebKitFormBoundaryI12ukQBs3HdmPjvh--
' (length=253)
*/
}
或者如何将 Post 数据序列化(转换)为 object 或数组
我使用 Postman 和 header "Content-Type: application/json" 发送请求。
你能告诉我如何保存文件(图片)吗?
您可以用于 POST 请求:
$request->request->get('data');
对于 GET 请求:
$request->query->get('data');
对于 FILE 查询:
$request->files.
并提出您的问题 How to save image?
,您必须创建 uploads -> excels
:
$dir = $this->get('kernel')->getRootDir() . '/../web/uploads/images/';
$name = uniqid() . '.jpeg';
foreach ($request->files as $uploadedFile) {
$uploadedFile->move($dir, $name);
}
$file = $this->get('kernel')->getRootDir() . "/../web/uploads/images/" . $name;
if (file_exists($file)) {
echo "Successfully saved";
}
转储请求中的所有数据以查找可能存在的问题:$request->request->all();
$request->request->get('content');
POST: $request->request->get('<propertyName>');
获取:$request->query->get('<propertyName>');