Rails 4.2.5 link_to 删除方法

Rails 4.2.5 link_to delete method

我对 link_to 助手的嵌套删除方法有疑问。

这是我的路线:

resources :restaurants, only: [:new, :show, :edit, :index,:create] do
  resources :reservations, only: [:new, :show, :edit, :index, :create]
  resources :reviews
end

这是我的审核控制器操作:

def destroy
  @review = Review.find(params[:id])
  @review.destroy
end

和我在 user#show 上的代码:

<div class="panel-body">
<h1> <%= pluralize(@user.reviews.count ,'review') %> from <%=      @user.name %> </h1>
    <% @user.reviews.order(created_at: :desc).each do |review| %>
    <ul>
      <li><em>Review for restaurant: </em><%= review.restaurant.name %></li>
      <em>Review comment: </em> <%= review.comment %></br>
      <%= link_to 'edit comment', edit_restaurant_review_path(review.restaurant_id, review.id) %>
      <%= link_to 'delete comment', restaurant_review_path( @user, review.id ) , method: :delete, data:{confirm:"are you sure you want to delete this review"} %>
    </ul>
    <% end %>
</div>

这是我的路线:

restaurant_reviews GET    /restaurants/:restaurant_id/reviews(.:format)               reviews#index
                        POST   /restaurants/:restaurant_id/reviews(.:format)               reviews#create
  new_restaurant_review GET    /restaurants/:restaurant_id/reviews/new(.:format)           reviews#new
 edit_restaurant_review GET    /restaurants/:restaurant_id/reviews/:id/edit(.:format)      reviews#edit
      restaurant_review GET    /restaurants/:restaurant_id/reviews/:id(.:format)           reviews#show
                        PATCH  /restaurants/:restaurant_id/reviews/:id(.:format)           reviews#update
                        PUT    /restaurants/:restaurant_id/reviews/:id(.:format)           reviews#update
                        DELETE /restaurants/:restaurant_id/reviews/:id(.:format)           reviews#destroy

我似乎无法删除我的评论。我传递了错误的变量吗? 到 'restaurant_review_path'?我的路线似乎是正确的。因为我的编辑 link_to 助手正在工作。

restaurant_review_path( @user, review.id ) 是错误的。您将 @user 作为 restaurant 参数传递,这将生成具有错误 ID 的 link。

你应该给它一个餐厅(或餐厅 ID)和评论,而不是用户和评论 ID,就像你在上一行编辑 link.

restaurant_review_path(review.restaurant_id, review.id)