Python 3.0 - 如何输出计数最多的字符？

Question

所以我能够创建一个程序来计算我计算机上的文本文件中元音（特别是 e i o）的数量。但是，我终生无法弄清楚如何显示哪一个出现得最多。我以为我会说

for ch in 'i':
    return numvowel?

我只是不太确定这一步是什么。我基本上希望它最后输出 "The letter, i, occurred the most in the text file"

def vowelCounter():
    inFile = open('file.txt', 'r')
    contents = inFile.read()

    # variable to store total number of vowels
    numVowel = 0

    # This counts the total number of occurrences of vowels o e i.
    for ch in contents:
        if ch in 'i':
            numVowel = numVowel + 1
        if ch in 'e':
            numVowel = numVowel + 1    
        if ch in 'o':
            numVowel = numVowel + 1

    print('file.txt has', numVowel, 'vowel occurences total')
    inFile.close()

vowelCounter()

Answer 1

如果你想显示哪一个出现的次数最多，你必须记录每个个单独的元音，而不是像你所做的那样只记录 1 个总数。

保留 3 个单独的计数器（您关心的 3 个元音中的每一个一个），然后您可以通过将它们相加得到总数，或者如果您想找出哪个元音出现次数最多，您可以简单地比较这 3 个元音柜台一探究竟。

Answer 2

尝试使用正则表达式； https://docs.python.org/3.5/library/re.html#regular-expression-objects

import re

def vowelCounter():

    with open('file.txt', 'r') as inFile:

        content = inFile.read()

        o_count = len(re.findall('o',content))
        e_count = len(re.findall('e',content))
        i_count = len(re.findall('i',content))

        # Note, if you want this to be case-insensitive,
        # then add the addition argument re.I to each findall function

        print("O's: {0}, E's:{1}, I's:{2}".format(o_count,e_count,i_count))

vowelCounter()

Answer 3

你可以这样做：

vowels = {} # dictionary of counters, indexed by vowels

for ch in contents:
    if ch in ['i', 'e', 'o']:
        # If 'ch' is a new vowel, create a new mapping for it with the value 1
        # otherwise increment its counter by 1
        vowels[ch] = vowels.get(ch, 0) + 1

print("'{}' occured the most."
    .format(*[k for k, v in vowels.items() if v == max(vowels.values())]))

Answer 4

Python 声称拥有 "batteries included"，这是一个 class 的典型案例。 class collections.Counter 做的差不多。

from collections import Counter

with open('file.txt') as file_
    counter = Counter(file_.read())

print 'Count of e: %s' % counter['e']
print 'Count of i: %s' % counter['i']
print 'Count of o: %s' % counter['o']

Answer 5

让vowels = 'eio'，然后

{ i: contents.count(i) for i in vowels }

对于 vowels 中的每个项目，计算在 contents 中出现的次数，并将其添加为结果词典的一部分（注意理解中的环绕大括号）。

Python 3.0 - 如何输出计数最多的字符？

Python 3.0 - How do I output which character is counted the most?

python

charactercount