捕获异常时无限循环

Question

我正在尝试从 System.in 中获取一个整数，并且我想捕获最终的错误。这是代码：

int dim;
boolean done = false;

while(!done)
  {
     try
     {
        dim = in.nextInt();
        done=true;
     }
     catch(InputMismatchException e)
     {
        System.out.println("I need an integer");
     }
  }

我得到的结果是错误字符串的无限循环。我做错了什么？我是否试图捕获错误的异常？

Answer 1

"When a scanner throws an InputMismatchException, the scanner will not pass the token that caused the exception, so that it may be retrieved or skipped via some other method."Oracle

捕获异常时无限循环

Infinite loop while catching an exception

java

exception

try-catch

infinite-loop

while-loop