UI-网格分页模板可编辑
UI-Grid pagination template editable
有什么方法可以从 ui-grid
编辑分页模板
需要删除蓝色四舍五入并替换该页中总行数的选定行索引值
有哪位大神能帮帮忙,先谢谢了!!!!!!
我认为你应该使用 API
控制的分页
http://ui-grid.info/docs/#/tutorial/214_pagination
像这样:
<div class="left" >
<a ng-click="page >= 1 ? gridApi.pagination.seek(1): '' "><i class="material-icons left">skip_previous</i></a>
<a ng-click="page >= 1 ? gridApi.pagination.previousPage() : '' "><i class="material-icons left">fast_rewind</i></a>
{{page}} / {{pages}}
<a ng-click="page < pages ? gridApi.pagination.nextPage() : '' "><i class="material-icons">fast_forward</i></a>
<a ng-click="page < pages ? gridApi.pagination.seek(pages) : '' "><i class="material-icons">skip_next</i></a>
</div>
使用分页模板选项:
self.gridOptions = {
enablePaginationControls: true,
paginationTemplate: $http.get('/Content/paging-control-template.html', { cache: $templateCache }).then(function (response) {
return response.data;
})}
有什么方法可以从 ui-grid
编辑分页模板需要删除蓝色四舍五入并替换该页中总行数的选定行索引值
有哪位大神能帮帮忙,先谢谢了!!!!!!
我认为你应该使用 API
控制的分页http://ui-grid.info/docs/#/tutorial/214_pagination
像这样:
<div class="left" >
<a ng-click="page >= 1 ? gridApi.pagination.seek(1): '' "><i class="material-icons left">skip_previous</i></a>
<a ng-click="page >= 1 ? gridApi.pagination.previousPage() : '' "><i class="material-icons left">fast_rewind</i></a>
{{page}} / {{pages}}
<a ng-click="page < pages ? gridApi.pagination.nextPage() : '' "><i class="material-icons">fast_forward</i></a>
<a ng-click="page < pages ? gridApi.pagination.seek(pages) : '' "><i class="material-icons">skip_next</i></a>
</div>
使用分页模板选项:
self.gridOptions = {
enablePaginationControls: true,
paginationTemplate: $http.get('/Content/paging-control-template.html', { cache: $templateCache }).then(function (response) {
return response.data;
})}