无法让 ip2long() 工作

Question

我正在尝试比较一些存储为字符串的 IP 地址。我读到有关 ip2long() 将字符串转换为整数的信息，所以我正在研究它，看看它是否能满足我的要求。所以，最初，我只是想看看转换后的 IP 长什么样。我写了下面的代码来查看，但没有任何内容被转换。我不明白我做错了什么。这是代码：

<?php
foreach($form->data[vicondb] as $video_net_key) 
{
    if ($video_net_key['ipaddress'] != null)
    {
        echo "The IP address is " . $video_net_key['ipaddress'];
        $iplong = ip2long($video_net_key['ipaddress']);
        echo " --- The ip long conversion is " . $iplong . "<br>";
    }

} // End foreach($form->data[vicondb] as $video_net_key)

echo "End of both foreach statements<br>";
?>

这是结果示例：

The IP address is 172.26.0.10 --- The ip long conversion is

The IP address is 172.26.0.31 --- The ip long conversion is

The IP address is 172.26.0.32 --- The ip long conversion is

The IP address is 172.26.0.33 --- The ip long conversion is

这里是 IP 的 var_dump() 示例并转换为整数：

string(12) "172.26.0.10 "
bool(false)
string(12) "172.26.0.31 "
bool(false)
string(12) "172.26.0.32 "
bool(false)

Answer 1

可能类似这样

"Because PHP's integer type is signed, and many IP addresses will result in negative integers on 32-bit architectures, you need to use the "%u" sprintf() 或 printf() 的格式化程序以获取未签名 IP 地址的字符串表示形式。" From ip2long php.net article

这应该有效：

echo " --- The ip long conversion is " . sprintf("%u", ip2long($video_net_key['ipaddress'])) . "<br>";

Answer 2

您需要 trim IP，因为它似乎有尾随 space 并且无效：

$iplong = ip2long(trim($video_net_key['ipaddress']));

无法让 ip2long() 工作

Can't get ip2long() to work

php

ip

ip2long