输入值增量的总和数组
Sum array of the increment of input values
我正在尝试编写一个接受两个输入值的求和数组函数。第一个输入值逐渐增加,直到达到第二个输入的值。例如,如果下限为“2”,上限为“5”,则总和为 2 + (2+1) + (2+2) + (2+3) + (2+4) + (2+ 5) = 27. 我试过使用变量 'i' 添加到 lowerLimit 并逐渐增加直到 (i <= (upperLimit - lowerLimit) 但我不确定如何写总和数组,或者求和数组是否是解决此问题的最佳方法。感谢您的帮助。
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第7题代码:
</pre>
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<div id="result"></div>
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<script>
$(document).ready(function () {
var lowerLimit = 0;
var upperLimit = 0;
function range(lowerLimit, upperLimit){
var lowerLimit = parseInt(prompt("What number would you like to being with?"));
if (isNaN(lowerLimit)) {
alert("That's not a number, please retry.");
var lowerLimit = prompt("Please re-enter a number.");
}
var upperLimit = parseInt(prompt("What number would you like to end with?"));
if (isNaN(upperLimit)) {
alert("That's not a number, please retry.");
var upperLimit = prompt("Please re-enter a number.");
}
/* var arr = [upperLimit, lowerLimit, i];
for(i = 1; i <= (upperLimit - lowerLimit); i++){
var equation = lowerLimit + (lowerLimit+i);
}*/
//ends function
}
//ends document ready function
});
</script>
数组有什么用?
您可以直接添加它们并在不使用数组的情况下给出输出...
试试这个代码:
var sum=lowerLimit;
for(i=1; i<=upperLimit; i++){
sum += (lowerLimit+i);
}
抱歉,代码有误
var sum=lowerlimit;
for(i=1; i<=upperLimit; i++){
sum += (lowerLimit+i);
}
我正在尝试编写一个接受两个输入值的求和数组函数。第一个输入值逐渐增加,直到达到第二个输入的值。例如,如果下限为“2”,上限为“5”,则总和为 2 + (2+1) + (2+2) + (2+3) + (2+4) + (2+ 5) = 27. 我试过使用变量 'i' 添加到 lowerLimit 并逐渐增加直到 (i <= (upperLimit - lowerLimit) 但我不确定如何写总和数组,或者求和数组是否是解决此问题的最佳方法。感谢您的帮助。
Q7 显示
Q7
<!-- Question 7 Start -->
<div role="tabpanel" class="tab-pane tab-pane active" id="q6">
<div class="row">
<div class="col-md-12">
<pre>
第7题代码:
</pre>
</div>
<div class="col-md-12">
<!-- button -->
<button id="button" class="btn btn-default" type="button">Question Seven Solution</button>
</div>
<div class="col-md-12">
<!-- result -->
<div id="result"></div>
</div>
</div>
</div>
<script>
$(document).ready(function () {
var lowerLimit = 0;
var upperLimit = 0;
function range(lowerLimit, upperLimit){
var lowerLimit = parseInt(prompt("What number would you like to being with?"));
if (isNaN(lowerLimit)) {
alert("That's not a number, please retry.");
var lowerLimit = prompt("Please re-enter a number.");
}
var upperLimit = parseInt(prompt("What number would you like to end with?"));
if (isNaN(upperLimit)) {
alert("That's not a number, please retry.");
var upperLimit = prompt("Please re-enter a number.");
}
/* var arr = [upperLimit, lowerLimit, i];
for(i = 1; i <= (upperLimit - lowerLimit); i++){
var equation = lowerLimit + (lowerLimit+i);
}*/
//ends function
}
//ends document ready function
});
</script>
数组有什么用? 您可以直接添加它们并在不使用数组的情况下给出输出...
试试这个代码:
var sum=lowerLimit;
for(i=1; i<=upperLimit; i++){
sum += (lowerLimit+i);
}
抱歉,代码有误
var sum=lowerlimit;
for(i=1; i<=upperLimit; i++){
sum += (lowerLimit+i);
}