从 while 循环中跳出

Question

我写了一个简单的骰子游戏，除了我正在努力解决的部分外，它按预期工作，即如何在按下特定键的情况下结束游戏。我知道我犯了一个简单的错误（嗯，我是一个初学者），但如果你能指出代码有什么问题，我会很高兴。

谢谢！

import random



def game():
    while True:

        userRoll = int(raw_input("Enter a number from 1 to 10 [press q to end the game]: "))
        compRoll = random.randrange(1, 11)

        print "You rolled " + str(userRoll) 
        print "Computer rolled " + str(compRoll)

        if userRoll > compRoll and userRoll > 0 and userRoll < 11:
            print "You win!"

        elif userRoll == compRoll:
            print "It's a tie!"

        elif userRoll < compRoll:
            print "Computer wins!"

        elif userRoll == 'q':
            print "bye"
            break

        else:
            print "You must enter number from 1 to 10. Try again..."

game()

Answer 1

此代码没有用：

    elif userRoll == 'q':
        print "bye"
        break

在该代码执行时，您已经将 userRoll 转换为整数。所以，如果永远不能被q。以下代码在转换为整数之前测试 userRoll == 'q'：

import random

def game():
    while True:

        userRoll = raw_input("Enter a number from 1 to 10 [press q to end the game]: ")
        if userRoll == 'q':
            print "bye"
            break
        userRoll = int(userRoll)

        compRoll = random.randrange(1, 11)

        print "You rolled " + str(userRoll)_
        print "Computer rolled " + str(compRoll)

        if userRoll > compRoll and userRoll > 0 and userRoll < 11:
            print "You win!"

        elif userRoll == compRoll:
            print "It's a tie!"

        elif userRoll < compRoll:
            print "Computer wins!"

        else:
            print "You must enter number from 1 to 10. Try again..."

game()

从 while 循环中跳出

break from the while loop

while-loop

python-2.7