如果小时数相同并且天数是连续的，则对天数进行分组奇连字符否则逗号

Question

我有一个代码，可以将商店营业时间相似的日子合并在一起。例如，如果我们有：

<?php

$openHours = array(
    'Mon' => '9am-7pm',
    'Tue' => '9am-7pm',
    'Wed' => '9am-7pm',
    'Thu' => '9am-6pm',
    'Fri' => 'closed',
    'Sat' => '9am-10pm',
    'Sun' => '9am-10pm'
);


foreach($openHours as $k => $v)
    $array[$v][] = $k;

foreach($array as $time => $days)
    echo implode(",", $days) . " " . $time . PHP_EOL;

?>

结果如下所示。

Mon,Tue,Wed 9am-7pm
Thu 9am-6pm
Fri closed
Sat,Sun 9am-10pm

我想要什么？

如果日期是连续的，我想用连字符连接，如果不是连续的，我想在下面的示例中添加逗号。

结果应该是这样

Mon-Wed 9am-7pm     // Hyphenate as days are consecutive and more than 2
Thu 9am-6pm
Fri closed
Sat,Sun 9am-10pm    // Adds comma as there are only 2

Answer 1

试试这个。

更新 2

<?php
$openHours = array(
    'Mon' => '9am-7pm',
    'Tue' => '9am-7pm',
    'Wed' => '9am-7pm',
    'Thu' => '9am-10pm',
    'Fri' => 'closed',
    'Sat' => '9am-10pm',
    'Sun' => '9am-10pm'
);
$new_array = array();
foreach($openHours as $key => $value)
{
  if(in_array($value,$new_array))
  {
     $key_new = array_search($value, $new_array);//to get the key of element
     unset($new_array[$key_new]); //remove the element
     $key_new = $key_new.','.$key; //updating the key
     $new_array[$key_new] = $value; //inserting new element to the key 
  }
  else
  {
    $new_array[$key] = $value;
  }
}

foreach ($new_array as $days=>$time){
    $daylist = explode(',',$days);
    if ($time!='closed'){
    if (count($daylist)>2){
        $limit = count($daylist)-1;
        $first = $daylist[0];
        $last = $daylist[$limit];
        //loop will go here.
        if (date('D', strtotime('+'.$limit.' days', strtotime($first)))==$last){
            echo $first.'-'.$last.' '.$time.'<br>';
        } else {
            $sep = '';
            foreach ($daylist as $sepdays){
                echo $sep.$sepdays;
                $sep = ',';
            }
            echo ' '.$time.'<br>';
        }

    } else {
        echo $days.' '.$time.'<br>';
    }
    } else {
        $daylist = explode(',',$days);
        foreach ($daylist as $sepdays){
                echo $sepdays.' '.$time.'<br>';
            }
    }

}
?>

结果

Mon-Wed 9am-7pm
Fri closed
Thu,Sat,Sun 9am-10pm

Answer 2

你可以这样使用：

$openHours = array(
    'Mon' => '9am-7pm',
    'Tue' => '9am-7pm',
    'Wed' => '9am-7pm',
    'Thu' => '9am-6pm',
    'Fri' => 'closed',
    'Sat' => '9am-10pm',
    'Sun' => '9am-10pm'
);


foreach($openHours as $k => $v){
    $array[$v][] = $k;
}

foreach($array as $time => $days){
  if(count($days) > 2){ // if count more than two days
    echo current($days)."-".end($days) . " " . $time . PHP_EOL."<br/>";
  }
  else{ // if normal like one or two days
    echo implode(",", $days) . " " . $time . PHP_EOL."<br/>";
  }
}

结果：

Mon-Wed 9am-7pm
Thu 9am-6pm
Fri closed
Sat,Sun 9am-10pm

旁注：

如果您想将 Sat,Sun 用作 Sat-Sun 而不仅仅是条件 if(count($days) > 1){.

更新 1：

例如，如果 Fri 和 Tue 关闭，这将起作用。

<?php 
$openHours = array(
    'Mon' => '9am-7pm',
    'Tue' => 'closed',
    'Wed' => '9am-7pm',
    'Thu' => '9am-6pm',
    'Fri' => 'closed',
    'Sat' => '9am-10pm',
    'Sun' => '9am-10pm'
);


foreach($openHours as $k => $v){
    $array[$v][] = $k;
}

foreach($array as $time => $days){
  if(count($days) > 2 && $time != 'closed'){ // if count more than two days
    echo current($days)."-".end($days) . " " . $time . PHP_EOL."<br/>";
  }
  elseif($time == 'closed'){ // if count more than two days
    echo implode(" closed<br/>", $days) . " " . $time . PHP_EOL."<br/>";
  }
  else{ // if normal like one or two days
    echo implode(",", $days) . " " . $time . PHP_EOL."<br/>";
  }
}
?>

结果：

Mon,Wed 9am-7pm
Tue closed
Fri closed
Thu 9am-6pm
Sat,Sun 9am-10pm

如果小时数相同并且天数是连续的，则对天数进行分组奇连字符否则逗号

Grouping Days if hours are same and if days are consecutive add hypenate else comma

php

days