AS3:如何检查,所有的zip文件都已经解压了?
AS3: How to check, all zip files has been extracted?
如何检查所有的zip文件是否已经解压?
var reader: ZipFileReader = new ZipFileReader();
reader.addEventListener(ZipEvent.ZIP_DATA_UNCOMPRESS, zipDataUncompressHandler);
var zipFile: File = new File(zipFilePath);
reader.open(zipFile);
var list: Array = reader.getEntries();
zipFileCount = list.length;
trace(zipFileCount + " Numbers of items");
for each(var entry: ZipEntry in list) {
var filename: String = entry.getFilename();
if (entry.isDirectory()) {
trace("DIR --->" + filename);
} else {
trace("FILE --->" + filename + "(" + entry.getCompressRate() + ")");
reader.unzipAsync(entry);
}
zipFileWritedCount = zipFileWritedCount + 1;
}
function zipDataUncompressHandler(e: ZipEvent): void {
var entry: ZipEntry = e.entry;
var zfile: File = File.userDirectory.resolvePath('somefolder' + File.separator + entry.getFilename());
var fs: FileStream = new FileStream();
fs.open(zfile, FileMode.WRITE);
fs.writeBytes(e.data);
fs.close();
trace("Refresh Scene");
//include "RefreshScene.as";
}
我的文件已提取,但我需要检查所有文件是否确实已提取。
有什么办法可以做到吗
我在处理 zip 文件时使用 airxzip。
另外,如果我可以添加一个装载机。
你可以缩短zipFileWritedCount = zipFileWritedCount + 1;
仅使用 zipFileWritedCount +=1;
甚至
zipFileWritedCount++;
- 无论如何检查 "all files extracted" 金额你可以试试
Equality ==
operator as mentioned in the manual.
快速示例:
for each(var entry: ZipEntry in list)
{
var filename: String = entry.getFilename();
if ( entry.isDirectory() ) { trace("DIR --->" + filename); }
else
{
trace("FILE --->" + filename + "(" + entry.getCompressRate() + ")");
reader.unzipAsync(entry);
}
zipFileWritedCount += 1; //add plus 1
if ( zipFileWritedCount == zipFileCount ) //if Equal to zipFileCount..
{
trace ("unzipped all files...");
trace ("zipFileCount: " + zipFileCount + " -VS- " + "zipFileWritedCount: " + zipFileWritedCount )
}
}
如何检查所有的zip文件是否已经解压?
var reader: ZipFileReader = new ZipFileReader();
reader.addEventListener(ZipEvent.ZIP_DATA_UNCOMPRESS, zipDataUncompressHandler);
var zipFile: File = new File(zipFilePath);
reader.open(zipFile);
var list: Array = reader.getEntries();
zipFileCount = list.length;
trace(zipFileCount + " Numbers of items");
for each(var entry: ZipEntry in list) {
var filename: String = entry.getFilename();
if (entry.isDirectory()) {
trace("DIR --->" + filename);
} else {
trace("FILE --->" + filename + "(" + entry.getCompressRate() + ")");
reader.unzipAsync(entry);
}
zipFileWritedCount = zipFileWritedCount + 1;
}
function zipDataUncompressHandler(e: ZipEvent): void {
var entry: ZipEntry = e.entry;
var zfile: File = File.userDirectory.resolvePath('somefolder' + File.separator + entry.getFilename());
var fs: FileStream = new FileStream();
fs.open(zfile, FileMode.WRITE);
fs.writeBytes(e.data);
fs.close();
trace("Refresh Scene");
//include "RefreshScene.as";
}
我的文件已提取,但我需要检查所有文件是否确实已提取。 有什么办法可以做到吗
我在处理 zip 文件时使用 airxzip。
另外,如果我可以添加一个装载机。
你可以缩短
zipFileWritedCount = zipFileWritedCount + 1;
仅使用
zipFileWritedCount +=1;
甚至zipFileWritedCount++;
- 无论如何检查 "all files extracted" 金额你可以试试
Equality ==
operator as mentioned in the manual.
快速示例:
for each(var entry: ZipEntry in list)
{
var filename: String = entry.getFilename();
if ( entry.isDirectory() ) { trace("DIR --->" + filename); }
else
{
trace("FILE --->" + filename + "(" + entry.getCompressRate() + ")");
reader.unzipAsync(entry);
}
zipFileWritedCount += 1; //add plus 1
if ( zipFileWritedCount == zipFileCount ) //if Equal to zipFileCount..
{
trace ("unzipped all files...");
trace ("zipFileCount: " + zipFileCount + " -VS- " + "zipFileWritedCount: " + zipFileWritedCount )
}
}