Python timedelta error: skipping a day when trying to get tomorrow

Question

我有以下代码：

import time
from datetime import date, datetime, timedelta


def getNextDay(last_day):
    #Returns tomorrows timestamp at two times: 00:00 and 23:59
    last_day = datetime.utcfromtimestamp(last_day)
    tomorrow = last_day + timedelta(days=1)
    tomorrow_start = datetime(tomorrow.year, tomorrow.month, tomorrow.day, 0, 0, 0, 0)
    tomorrow_end = datetime(tomorrow.year, tomorrow.month, tomorrow.day, 23, 59, 0, 0)
    return [time.ctime(int(tomorrow_start.strftime("%s"))), time.ctime(int(tomorrow_end.strftime("%s")))]


last_day = 1370054073 #unix-timestamp

print "The day is:"
print time.ctime(last_day)

print "The next day is:"
print getNextDay(last_day)

当我运行它的输出是：

The day is:
Fri May 31 23:34:33 2013
The next day is:
['Sun Jun  2 00:00:00 2013', 'Sun Jun  2 23:59:00 2013']

我找不到问题，因为 getNextDay() 函数似乎是正确的：我想在 00:00 和 23:59 从 1370054073 获取明天。但是它跳过了一天，第二天的输出应该是 ['Sat Jun 1 00:00:00 2013', 'Sat Jun 1 23:59:00 2013']

谁能告诉我哪里做错了？

Answer 1

来自time.ctime的文档：

Convert a time expressed in seconds since the epoch to a string representing local time. If secs is not provided or None, the current time as returned by time() is used. ctime(secs) is equivalent to asctime(localtime(secs)). Locale information is not used by ctime().

因此，当您使用 print time.ctime(last_day) 时，您会看到基于当地时间的时间：

Fri May 31 23:34:33 2013

但是，当我使用它时，我看到了不同的时间：

Sat Jun  1 08:04:33 2013

您可以获得实际的UTC时间如下：

>>> datetime.utcfromtimestamp(last_day)
datetime.datetime(2013, 6, 1, 2, 34, 33)

而且，如您所见，它已经是 June 1，因此您的函数工作正常，不会跳过任何一天。

Python timedelta error: skipping a day when trying to get tomorrow

Python timedelta error: skipping a day when trying to get tomorrow

python

timestamp

timedelta

unix-timestamp