使用作者姓名存储数据 - laravel 5.2

Question

我与我的模型用户和报告有很多关系。我想为报告设置作者姓名。（点赞博客-post 作者）

我的模特用户：

public function reports() {
    return $this->hasMany('App\Report', 'author_id');
}

模型报告

public function user() {
    return $this->belongsTo('App\User', 'author_id');
}

和我的控制器：

public function create()
{
    $category = Category::lists('title','id');
    return view('dash.reports.create')->with('category', $category);
}

/**
 * Store a newly created resource in storage.
 *
 * @return void
 */
public function store(Request $request)
{
    $this->validate($request, ['title' => 'required', ]);

    Report::create($request->all());

    Session::flash('flash_message', 'Report added!');

    return redirect('dash/reports');
}

我可以在 phpmyadmin 中进行设置，但是我该如何使用我的控制器进行设置？

编辑：我的观点：

{!! Form::open(['url' => '/dash/reports', 'class' => 'form-horizontal']) !!}

       <div class="form-group {{ $errors->has('title') ? 'has-error' : ''}}">
            {!! Form::label('title', 'Servizio', ['class' => 'col-sm-3 control-label']) !!}
            <div class="col-sm-6">
                {!! Form::text('title', null, ['class' => 'form-control', 'required' => 'required']) !!}
                {!! $errors->first('title', '<p class="help-block">:message</p>') !!}
            </div>
        </div>

       <div class="form-group {{ $errors->has('title') ? 'has-error' : ''}}">
            {!! Form::label('date', 'Data lavorativa', ['class' => 'col-sm-3 control-label']) !!}

            <div class="col-sm-2">
                {!! Form::selectRange('day', 1, 31, null,  ['class' => 'form-control']) !!}
                {!! $errors->first('day', '<p class="help-block">:message</p>') !!}
            </div>

            <div class="col-sm-2">
                {!! Form::selectMonth('month', null,  ['class' => 'form-control']) !!}
                {!! $errors->first('month', '<p class="help-block">:message</p>') !!}
            </div>

            <div class="col-sm-2">
                {!! Form::select('year', array('2016' => '2016', '2015' => '2015'), null,  ['class' => 'form-control']) !!}
                {!! $errors->first('year', '<p class="help-block">:message</p>') !!}
            </div>
        </div>

        <div class="form-group {{ $errors->has('category_id') ? 'has-error' : ''}}">
            {!! Form::label('category_id', 'Cliente', ['class' => 'col-sm-3 control-label']) !!}
            <div class="col-sm-6">
                {!! Form::select('category_id', $category, null, ['class' => 'form-control'] ) !!}
                {!! $errors->first('category_id', '<p class="help-block">:message</p>') !!}
            </div>
        </div>


<div class="form-group">
    <div class="col-sm-offset-3 col-sm-3">
        {!! Form::submit('Create', ['class' => 'btn btn-primary form-control']) !!}
    </div>
</div>
{!! Form::close() !!}

Answer 1

很简单。用这个替换 Report::create...。

$user   = Auth::user();
$report = new Report($request->all());
$report->author()->associate($user);
$report->save();

确保您 use Auth; 位于顶部。

这使用Auth对象获取当前用户，
使用 $request 数据构建一个新的 Report 没有保存，
告诉报表我们将 $user 关联为模型的 author，
保存带有作者信息的报告。

Answer 2

解决方案：

public function store(Request $request)
{
    $this->validate($request, ['title' => 'required', ]);

    $user = Auth::user()->id;
    $report = new Report($request->all());
    $report->author_id = $user;
    $report->save();

    Session::flash('flash_message', 'Report added!');

    return redirect('dash/reports');
}

使用作者姓名存储数据 - laravel 5.2

storing data with name of author - laravel 5.2

has-many

relation

laravel

eloquent