IOS

Question

我有这个位来检索两个用户之间的所有消息：

let user1 = "john"
let user2 = "mark"
let predicateUser1To2 = NSPredicate(format: "user1 == %@", user1)
let predicateUser2From1 = NSPredicate(format: "user2 == %@", user2)

let predicateUser2To1 = NSPredicate(format: "user2 == %@", user1)
let predicateUser1From2 = NSPredicate(format: "user1 == %@", user2)

let predicate1To2 = NSCompoundPredicate(andPredicateWithSubpredicates: [predicateUser1To2, predicateUser2From1])
let predicate2To1 = NSCompoundPredicate(andPredicateWithSubpredicates: [predicateUser1From2, predicateUser2To1])
let predicate = NSCompoundPredicate(orPredicateWithSubpredicates: [predicate1To2, predicate2To1])

let query = CKQuery(recordType: "Chat", predicate: predicate)

但是它抛出了下面的错误。好像评估正确了，为什么错误！？

*** Terminating app due to uncaught exception 'CKException', reason: 'Invalid predicate: (user1 == "john" AND user2 == "mark") OR (user1 == "mark" AND user2 == "john") (Error Domain=CKErrorDomain Code=12 "(user1 == "john" AND user2 == "mark") OR (user1 == "mark" AND user2 == "john") is not a comparison predicate" UserInfo={NSLocalizedDescription=(user1 == "john" AND user2 == "mark") OR (user1 == "mark" AND user2 == "john") is not a comparison predicate, ck_isComparisonError=true})'

Answer 1

OR CloudKit 不支持查询。有关详细信息，请参阅： https://developer.apple.com/library/ios/documentation/CloudKit/Reference/CKQuery_class/

在很多情况下，您可以使用 in 谓词来解决这个问题，但这只适用于一个字段。在您的情况下，您可能会考虑像这样的谓词：

NSPredicate(format: "user1 in %@ AND user2 in %@", ["john", "mark"], ["john", "mark"])

这个和你的样本还是不完全一样。 user1 可能与 user2 相同。例如，两者都可以是标记。在您的情况下，该记录未被选中，而在上面的示例中被选中。您可以添加一个额外的 AND 条件来排除这些条件。您可以添加：AND user1 != user2

如果查询变得更复杂并且无法进行 in 查询，那么您可以执行 2 个查询并合并结果。

IOS - Swift: OrPredicate in CloudKit 结果无效

IOS - Swift: OrPredicate in CloudKit results in invalid

nspredicate

swift

cloudkit