如何在服务器 sql 列中显示行值？

Question

我有这个 table 结构用于 SheduleWorkers table:

    CREATE TABLE SheduleWorkers
    (
         [Name] varchar(250),
         [IdWorker] varchar(250),    
         [IdDepartment] int,
         [IdDay] int,
         [Day] varchar(250)
    );


INSERT INTO SheduleWorkers ([Name],  [IdWorker],  [IdDepartment], [IdDay], [Day])
values 
('Sam', '001', 5, 1, 'Monday'),
('Lucas', '002', 5, 2, 'Tuesday'),
('Maria', '003', 5, 1, 'Monday'),
('José', '004', 5, 3, 'Wednesday'),
('Julianne', '005', 5, 3, 'Wednesday'),
('Elisa', '006', 18, 1, 'Monday'),
('Gabriel', '007', 23, 5, 'Friday');

我需要在每个工作日显示部门 5 在这一天工作的工人的姓名，如下所示：

MONDAY   TUESDAY   WEDNESDAY  THURSDAY  FRIDAY  SATURDAY
------   -------   ---------  --------  ------  -------
Sam       Lucas    Jose       
Maria              Julianne

如何得到这个结果，我接受建议，谢谢。

Answer 1

DECLARE @SheduleWorkers TABLE
    (
      [Name] VARCHAR(250) ,
      [IdWorker] VARCHAR(250) ,
      [IdDepartment] INT ,
      [IdDay] INT ,
      [Day] VARCHAR(250)
    );


INSERT  INTO @SheduleWorkers
        ( [Name], [IdWorker], [IdDepartment], [IdDay], [Day] )
VALUES  ( 'Sam', '001', 5, 1, 'Monday' ),
        ( 'Lucas', '002', 5, 2, 'Tuesday' ),
        ( 'Maria', '003', 5, 1, 'Monday' ),
        ( 'José', '004', 5, 3, 'Wednesday' ),
        ( 'Julianne', '005', 5, 3, 'Wednesday' ),
        ( 'Elisa', '006', 18, 1, 'Monday' ),
        ( 'Gabriel', '007', 23, 5, 'Friday' );

;
WITH    cte
          AS ( SELECT   Name ,
                        Day ,
                        ROW_NUMBER() OVER ( PARTITION BY Day ORDER BY [IdWorker] ) AS rn
               FROM     @SheduleWorkers
             )
    SELECT  [MONDAY] ,
            [TUESDAY] ,
            [WEDNESDAY] ,
            [THURSDAY] ,
            [FRIDAY] ,
            [SATURDAY]
    FROM    cte PIVOT( MAX(Name) FOR day IN ( [MONDAY], [TUESDAY], [WEDNESDAY],
                                              [THURSDAY], [FRIDAY], [SATURDAY] ) ) p

输出：

MONDAY  TUESDAY WEDNESDAY   THURSDAY    FRIDAY  SATURDAY
Sam     Lucas   José        NULL        Gabriel NULL
Maria   NULL    Julianne    NULL        NULL    NULL
Elisa   NULL    NULL        NULL        NULL    NULL

主要思想是 row_number window 通用 table 表达式中的函数，它将为您提供与一天中最大重复项一样多的行。

Answer 2

我建议您使用 PIVOT 和动态 SQL 来获取您需要的所有日期名称：

DECLARE @column nvarchar(max),
        @sql nvarchar(max)

;WITH cte AS (
SELECT DATENAME(WEEKDAY,0) as [Day], 1 as [Level]
UNION ALL
SELECT DATENAME(WEEKDAY,[Level]), [Level] + 1
FROM cte
WHERE [Level] < 7
)

SELECT @column = STUFF((SELECT ','+QUOTENAME([Day]) FROM cte ORDER BY [Level]FOR XML PATH('')),1,1,'')

SELECT @sql = 
'SELECT '+@column+'
FROM (
    SELECT Name, [Day], RANK() OVER (PARTITION BY [Day] ORDER BY [Day],IdWorker) as rn
    FROM #SheduleWorkers
) as p
PIVOT
(
MAX(NAMe) FOR [Day] IN ('+@column+')
) as pvt'

EXEC(@sql)

输出：

Monday  Tuesday Wednesday   Thursday    Friday  Saturday    Sunday
Sam     Lucas   Jose        NULL        Gabriel NULL        NULL
Maria   NULL    Julianne    NULL        NULL    NULL        NULL
Elisa   NULL    NULL        NULL        NULL    NULL        NULL

Answer 3

您可以为此使用数据透视表。请使用以下查询来解决您的问题。并使用分区。

SELECT  [Monday] , [Tuesday] , [Wednesday] , [Thursday] , [Friday], [SATURDAY]
FROM 
(SELECT [Day],[Name],RANK() OVER (PARTITION BY [Day] ORDER BY [Day],[Name]) as rnk
 FROM SheduleWorkers) p
 PIVOT(
Min([Name])
FOR [Day] IN
( [Monday] , [Tuesday] , [Wednesday] , [Thursday] , [Friday], [SATURDAY]  )
) AS pvt

如何在服务器 sql 列中显示行值？

How can I display rows values in columns sql server?

sql

sql-server

group-by

weekday

union-all