Neo4j：获取一组节点内的所有关系

Question

我有以下查询：

MATCH (d:Document)<-[o:OCCURS_IN]-(a:Alias)
WHERE LOWER(d.content) contains 'keyword'
WITH COUNT(o) as degree, a as a ORDER BY degree DESC LIMIT 20
MATCH (a)<-[:KNOWN_AS]-(ag:Agent)
RETURN ag;

我筛选了所有包含关键字的文档节点，并获取前 20 个别名节点，这些节点按它们连接到文档节点的频率排序。之后，收集并返回所有连接到 Alias 节点的代理。

这给了我一组代理节点。除此之外，我想获得这组代理节点中的所有关系。这意味着返回的节点集应该是相同的。只应添加这些节点之间的关系。

如何在没有额外查询的情况下实现此目的？

Answer 1

请继续您的查询：

MATCH (d:Document)<-[o:OCCURS_IN]-(a:Alias)
WHERE LOWER(d.content) contains 'keyword'
WITH COUNT(o) as degree, a as a ORDER BY degree DESC LIMIT 20
MATCH (a)<-[:KNOWN_AS]-(ag:Agent)
OPTIONAL MATCH (ag)-[r]-()
RETURN ag, collect(r) as relationships

Answer 2

以下是您如何获得原始查询返回的所有 Agent 节点之间的所有直接关系：

MATCH (d:Document)<-[o:OCCURS_IN]-(a:Alias)
WHERE LOWER(d.content) contains 'keyword'
WITH COUNT(o) as degree, a ORDER BY degree DESC LIMIT 20
MATCH (a)<-[:KNOWN_AS]-(ag:Agent)
WITH COLLECT(ag) AS ags
UNWIND ags AS ag1
UNIWND ags AS ag2
MATCH (ag1)-[r]->(ag2)
RETURN r;

Neo4j：获取一组节点内的所有关系

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