是否可以将带有换行符的单元格拆分为一个范围内的多行?
Is it possible to split cells with line breaks into multiple rows in a range?
我有一系列数据,其中一些单元格有换行符,我需要将换行符拆分为换行符下方的行,但其他单元格保持原样。如果有所不同,也有多个列。
我使用了下面提供的两个答案,并进行了一些调整以适合我的工作表,但都无法拆分所有单元格。我最后甚至都尝试了,但这也不起作用。
当A列有换行符时,它可以工作,但是当A列没有换行符而另一列有时,它就不起作用。如果A列没有换行符,我只需要将有换行符的行拆分并合并到下面的行即可。
代码如下:
end_row = range("A" & Rows.count).End(xlUp).row
range("A:A").TextToColumns Destination:=range("a1"), DataType:=xlDelimited, _
TextQualifier:=xlDoubleQuote, ConsecutiveDelimiter:=True, Tab:=False, _
Semicolon:=False, Comma:=False, Space:=False, Other:=False, OtherChar _
:=" ", FieldInfo:=Array(1, 1), TrailingMinusNumbers:=True
For i = 1 To end_row
row_added = False
For j = 1 To 4
If InStr(1, Cell, Chr(10)) <> 0 Then
If Not row_added Then
Rows(i + 1).Insert
row_added = True
end_row = end_row + 1
End If
Cells(i + 1, j) = Right(Cells(i, j), Len(Cells(i, j)) - InStr(1, Cell, Chr(10)))
Cells(i, j) = Left(Cells(i, j), InStr(1, Cell, Chr(10)) - 1)
End If
Next j
Next i
和
Sub LFtoRow()
Dim myWS As Worksheet, myRng As range
Dim LastRow As Long, iLoop As Long, jLoop As Long
Dim myString() As String
Set myWS = ActiveSheet
LastRow = myWS.Cells(myWS.Rows.count, 1).End(xlUp).row
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 1), Chr(10))
If UBound(myString, 1) > 0 Then
myWS.Rows(iLoop + 1 & ":" & iLoop + UBound(myString, 1)).Insert shift:=xlShiftDown
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 1) = myString(jLoop)
Next jLoop
End If
Next iLoop
End Sub
要么完全使用新代码,要么只在最后添加一些内容。我有一个正在发生的事情的例子,以及我希望它看起来像下面的样子。 (我知道它在照片中显示 B 列,但此时在 MACRO 中它在 A 列中)
发生了什么:
我需要发生的事情:
我会推荐类似于下面的代码来解决您的问题。它具有以下属性:
- 使用 Split 函数在 Chr(10) 上确定每行所需的字符串。 Chr(10) 是换行符。 Split 为您生成一个字符串数组。
- 为您插入正确的行数。
- 从下到上遍历您的范围,以便您处理完整的范围。
代码...
Sub LFtoRow()
Dim myWS As Worksheet, myRng As Range
Dim LastRow As Long, iLoop As Long, jLoop As Long
Dim myString() As String
Set myWS = Worksheets("Sheet1")
LastRow = myWS.Cells(myWS.Rows.Count, 1).End(xlUp).Row
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 1), Chr(10))
If UBound(myString, 1) > 0 Then
myWS.Rows(iLoop + 1 & ":" & iLoop + UBound(myString, 1)).Insert Shift:=xlShiftDown
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 1) = myString(jLoop)
Next jLoop
End If
Next iLoop
End Sub
当出现此输入时...
...生成此结果...
这是我的建议,应该处理所有列中的换行符。
我还删除了插入“;”的替换然后就此分裂。完整代码为:
end_row = Range("A" & Rows.Count).End(xlUp).Row
Range("A:A").TextToColumns Destination:=Range("a1"), DataType:=xlDelimited, _
TextQualifier:=xlDoubleQuote, ConsecutiveDelimiter:=True, Tab:=False, _
Semicolon:=False, Comma:=False, Space:=False, Other:=False, OtherChar _
:=" ", FieldInfo:=Array(1, 1), TrailingMinusNumbers:=True
For i = 1 To end_row
row_added = False
For j = 1 To 4
If InStr(1, Cell, Chr(10)) <> 0 Then
If Not row_added Then
Rows(i + 1).Insert
row_added = True
end_row = end_row + 1
End If
Cells(i + 1, j) = Right(Cells(i, j), Len(Cells(i, j)) - InStr(1, Cell, Chr(10)))
Cells(i, j) = Left(Cells(i, j), InStr(1, Cell, Chr(10)) - 1)
End If
Next j
Next i
这很可能不是最简洁的方法,但使用@OldUgly 的代码最终对我有用。
Sub LFtoRow()
Dim myWS As Worksheet, myRng As range
Dim LastRow As Long, iLoop As Long, jLoop As Long
Dim myString() As String
Set myWS = ActiveSheet
LastRow = myWS.Cells(myWS.Rows.count, 1).End(xlUp).row
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 1), Chr(10))
If UBound(myString, 1) > 0 Then
myWS.Rows(iLoop + 1 & ":" & iLoop + UBound(myString, 1)).Insert shift:=xlShiftDown
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 1) = myString(jLoop)
Next jLoop
End If
Next iLoop
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 2), Chr(10))
If UBound(myString, 1) > 0 Then
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 2) = myString(jLoop)
Next jLoop
End If
Next iLoop
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 3), Chr(10))
If UBound(myString, 1) > 0 Then
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 3) = myString(jLoop)
Next jLoop
End If
Next iLoop
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 4), Chr(10))
If UBound(myString, 1) > 0 Then
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 4) = myString(jLoop)
Next jLoop
End If
Next iLoop
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 5), Chr(10))
If UBound(myString, 1) > 0 Then
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 5) = myString(jLoop)
Next jLoop
End If
Next iLoop
End Sub
我有一系列数据,其中一些单元格有换行符,我需要将换行符拆分为换行符下方的行,但其他单元格保持原样。如果有所不同,也有多个列。
我使用了下面提供的两个答案,并进行了一些调整以适合我的工作表,但都无法拆分所有单元格。我最后甚至都尝试了,但这也不起作用。
当A列有换行符时,它可以工作,但是当A列没有换行符而另一列有时,它就不起作用。如果A列没有换行符,我只需要将有换行符的行拆分并合并到下面的行即可。
代码如下:
end_row = range("A" & Rows.count).End(xlUp).row
range("A:A").TextToColumns Destination:=range("a1"), DataType:=xlDelimited, _
TextQualifier:=xlDoubleQuote, ConsecutiveDelimiter:=True, Tab:=False, _
Semicolon:=False, Comma:=False, Space:=False, Other:=False, OtherChar _
:=" ", FieldInfo:=Array(1, 1), TrailingMinusNumbers:=True
For i = 1 To end_row
row_added = False
For j = 1 To 4
If InStr(1, Cell, Chr(10)) <> 0 Then
If Not row_added Then
Rows(i + 1).Insert
row_added = True
end_row = end_row + 1
End If
Cells(i + 1, j) = Right(Cells(i, j), Len(Cells(i, j)) - InStr(1, Cell, Chr(10)))
Cells(i, j) = Left(Cells(i, j), InStr(1, Cell, Chr(10)) - 1)
End If
Next j
Next i
和
Sub LFtoRow()
Dim myWS As Worksheet, myRng As range
Dim LastRow As Long, iLoop As Long, jLoop As Long
Dim myString() As String
Set myWS = ActiveSheet
LastRow = myWS.Cells(myWS.Rows.count, 1).End(xlUp).row
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 1), Chr(10))
If UBound(myString, 1) > 0 Then
myWS.Rows(iLoop + 1 & ":" & iLoop + UBound(myString, 1)).Insert shift:=xlShiftDown
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 1) = myString(jLoop)
Next jLoop
End If
Next iLoop
End Sub
要么完全使用新代码,要么只在最后添加一些内容。我有一个正在发生的事情的例子,以及我希望它看起来像下面的样子。 (我知道它在照片中显示 B 列,但此时在 MACRO 中它在 A 列中)
发生了什么:
我需要发生的事情:
我会推荐类似于下面的代码来解决您的问题。它具有以下属性:
- 使用 Split 函数在 Chr(10) 上确定每行所需的字符串。 Chr(10) 是换行符。 Split 为您生成一个字符串数组。
- 为您插入正确的行数。
- 从下到上遍历您的范围,以便您处理完整的范围。
代码...
Sub LFtoRow()
Dim myWS As Worksheet, myRng As Range
Dim LastRow As Long, iLoop As Long, jLoop As Long
Dim myString() As String
Set myWS = Worksheets("Sheet1")
LastRow = myWS.Cells(myWS.Rows.Count, 1).End(xlUp).Row
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 1), Chr(10))
If UBound(myString, 1) > 0 Then
myWS.Rows(iLoop + 1 & ":" & iLoop + UBound(myString, 1)).Insert Shift:=xlShiftDown
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 1) = myString(jLoop)
Next jLoop
End If
Next iLoop
End Sub
当出现此输入时...
...生成此结果...
这是我的建议,应该处理所有列中的换行符。
我还删除了插入“;”的替换然后就此分裂。完整代码为:
end_row = Range("A" & Rows.Count).End(xlUp).Row
Range("A:A").TextToColumns Destination:=Range("a1"), DataType:=xlDelimited, _
TextQualifier:=xlDoubleQuote, ConsecutiveDelimiter:=True, Tab:=False, _
Semicolon:=False, Comma:=False, Space:=False, Other:=False, OtherChar _
:=" ", FieldInfo:=Array(1, 1), TrailingMinusNumbers:=True
For i = 1 To end_row
row_added = False
For j = 1 To 4
If InStr(1, Cell, Chr(10)) <> 0 Then
If Not row_added Then
Rows(i + 1).Insert
row_added = True
end_row = end_row + 1
End If
Cells(i + 1, j) = Right(Cells(i, j), Len(Cells(i, j)) - InStr(1, Cell, Chr(10)))
Cells(i, j) = Left(Cells(i, j), InStr(1, Cell, Chr(10)) - 1)
End If
Next j
Next i
这很可能不是最简洁的方法,但使用@OldUgly 的代码最终对我有用。
Sub LFtoRow()
Dim myWS As Worksheet, myRng As range
Dim LastRow As Long, iLoop As Long, jLoop As Long
Dim myString() As String
Set myWS = ActiveSheet
LastRow = myWS.Cells(myWS.Rows.count, 1).End(xlUp).row
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 1), Chr(10))
If UBound(myString, 1) > 0 Then
myWS.Rows(iLoop + 1 & ":" & iLoop + UBound(myString, 1)).Insert shift:=xlShiftDown
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 1) = myString(jLoop)
Next jLoop
End If
Next iLoop
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 2), Chr(10))
If UBound(myString, 1) > 0 Then
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 2) = myString(jLoop)
Next jLoop
End If
Next iLoop
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 3), Chr(10))
If UBound(myString, 1) > 0 Then
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 3) = myString(jLoop)
Next jLoop
End If
Next iLoop
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 4), Chr(10))
If UBound(myString, 1) > 0 Then
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 4) = myString(jLoop)
Next jLoop
End If
Next iLoop
For iLoop = LastRow To 1 Step -1
myString = Split(myWS.Cells(iLoop, 5), Chr(10))
If UBound(myString, 1) > 0 Then
For jLoop = 0 To UBound(myString, 1)
myWS.Cells(iLoop + jLoop, 5) = myString(jLoop)
Next jLoop
End If
Next iLoop
End Sub