NSPredicate 用于精确匹配

NSPredicate for exact match

 NSArray *arrData = [NSArray arrayWithObjects:
                    @"cloud,country,plant",
                    @"country,cloud,plant",
                    @"country,plant,cloud",
                    @"clouds,country,plant"
                    ,@"country,clouds,plant",
                    nil];

从 NSArray 上面,我想要有单词 "cloud"

的对象

我试过下面的代码

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(self beginswith %@ OR self contains[CD] %@)",@"cloud",@",cloud"];
NSArray *arrResult = [arrData filteredArrayUsingPredicate:predicate];

但是它在 arrResult 中给出了所有 5 个对象。但我只需要 3 (0,1,2) 个对象。

尝试:

 NSPredicate* predicate = [NSPredicate predicateWithBlock:^(NSString* string, NSDictionary* options){

    NSArray* array = [string componentsSeparatedByString:@","];

    return [array containsObject:@"cloud"];

}];

试试下面的代码,

它会起作用,

 NSPredicate *hsPredicate = [NSPredicate predicateWithBlock:^BOOL(id  _Nonnull evaluatedObject, NSDictionary<NSString *,id> * _Nullable bindings) {
        NSArray *sepretArray =[((NSString*)evaluatedObject) componentsSeparatedByString:@","];
        NSPredicate *subPredicate = [NSPredicate predicateWithFormat:@"self == %@",@"cloud"];
        return  ([sepretArray filteredArrayUsingPredicate:subPredicate].count > 0);

    }];
    NSArray *arrResult = [arrData filteredArrayUsingPredicate:hsPredicate];

这个 trick.But 我不知道这是否是执行此操作的有效方法。

 NSArray *arrData = [NSArray arrayWithObjects:
                    @"cloud,country,plant",
                    @"country,cloud,plant",
                    @"country,plant,cloud",
                    @"clouds,country,plant"
                    ,@"country,clouds,plant",
                    nil];

NSMutableArray *resArray = [[NSMutableArray alloc]init];
for(NSString *tempString in arrData)
{
    NSArray *cache = [tempString componentsSeparatedByString:@","];
    if([cache containsObject:@"cloud"])
      {
        [resArray addObject:tempString];
      }
}