C++ 修复链接器 [错误]

C++ Fixing Linker [Error]

我仍在学习如何在头文件中使用 类,我 运行 遇到了一个问题。无论出于何种原因,当我转到 运行 程序时出现错误 "V3_Employee.cpp:(.text+0x3e): undefined reference to `Employee::print(std::string)'"。

我认为这与编译器与 .o 文件或类似文件的交互有关。

main.cpp

#include <iostream>
#include <string>
#include "V3_Employee.h"    //Including header file of for class Burrito

using namespace std;

int main()
{

    Employee Sean("Sean");

    return(0);

}

Employee.h

//Header guard
#ifndef V3_EMPLOYEE_H   //If this header has not already been included in main.cpp
#define V3_EMPLOYEE_H   //Then include the following lines of code

#include <string>

using namespace std;

class Employee  //Creating a class named 'Employee'
    {
        private:

            //Creating variables
            string m_name;

        //Creating a public interface
        public:

            //Creating a Construct
            Employee(string m_name);

            //Creating a 'Member function', another name for a function inside a class              
            void print(string m_name);
    };

endif //代码结束

Employee.cpp

#include "V3_Employee.h"
#include <iostream>
#include <string>

using namespace std;

Employee::Employee(string m_name)
    {
        print(name);
    }

void print(string name) //Defining the function 'print'
    {
        cout<<"Name: "<<m_name<<endl; 
    }

我还有另一个几乎完全相同的代码,而不是使用整数输入而不是字符串:

main2.cpp

#include <iostream>
#include "V2_Burrito.h" //Including header file of for class Burrito

using namespace std;

int main()
{

    Burrito Test(1);    //Setting 'Test' as an object of class 'Burrito' with an input of '1'

    return(0);

}

Burrito.h

//Header guard
#ifndef V2_BURRITO_H    //If this header has not already been included in main.cpp
#define V2_BURRITO_H    //Then include the following lines of code

class Burrito   //Creating a class named 'Burrito'
    {
        //Creating a public interface
        public:
            //Creating a 'Constructor', or a way to manipulate 'private' data
            Burrito(int a); //This constructor contains 1 input in the form of an integer

            //Creating a 'Member function', another name for a function inside a class
            void setType(int a);
    };

#endif  //End of code

感谢您提供的任何帮助!

void print(string name) 未在 class Employee 中定义,因此您的链接器抱怨找不到它。

您应该将代码更改为:

void Employee::print(string name) {
   ...
}

然后它被定义,链接器会找到这个函数。

顺便说一句,因为你只是打印字符串,所以最好通过const referense,所以最好像下面这样写:

void Employee::print(const string& name) {
   ...
}

但是也不好,因为print函数是Employee的成员函数,它知道要打印哪个变量,所以最好把你的代码改成:

void Employee::print() {
   cout<<"Name: "<<m_name<<endl;
}

那就有道理了