使用 UITapGestureRecognizer 传递参数

Question

有什么方法可以用 UITapGestureRecognizer 传递参数吗？我已经看到 objective-c 的答案，但找不到 swift

的答案

test.userInteractionEnabled = true
let tapRecognizer = UITapGestureRecognizer(target: self, action: Selector("imageTapped4:"))
// Something like text.myParamater
test.addGestureRecognizer(tapRecognizer)

然后在func imageTapped4()下接收myParameter{}

Answer 1

最好的方法是在触发函数 imageTapped64 时确定参数。您可以通过视图获取参数（查看@Developer Sheldon 的回答）或以许多其他方式。

Answer 2

一种方法是子class UITapGestureRecognizer 然后设置一个属性，我在下面发布了一个示例。您还可以对发件人进行一些检查，并检查是否等于某个标签，class，字符串，e.t.c

class ViewController: UIViewController {

    @IBOutlet weak var label1: UILabel!
    @IBOutlet weak var image: UIImageView!

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
        image.userInteractionEnabled = true;
        let tappy = MyTapGesture(target: self, action: #selector(self.tapped(_:)))
        image.addGestureRecognizer(tappy)
        tappy.title = "val"
    }

    func tapped(sender : MyTapGesture) {
        print(sender.title)
        label1.text = sender.title
    }
}

class MyTapGesture: UITapGestureRecognizer {
    var title = String()
}

SO上有很多例子，看看，祝你好运。

Answer 3

对于Swift 4

在视图中已加载

let label     =   UILabel(frame: CGRect(x: 0, y: h, width: Int(self.phoneNumberView.bounds.width), height: 30))
                label.textColor = primaryColor
                label.numberOfLines = 0
                label.font = title3Font
                label.lineBreakMode = .byWordWrapping
                label.attributedText = fullString

 let phoneCall = MyTapGesture(target: self, action: #selector(self.openCall))
        phoneCall.phoneNumber = "\(res)"
            label.isUserInteractionEnabled = true
            label.addGestureRecognizer(phoneCall)

功能为

@objc func openCall(sender : MyTapGesture) {
        let number = sender.phoneNumber
        print(number)
}

将Class写成

class MyTapGesture: UITapGestureRecognizer {
    var phoneNumber = String()
}

使用 UITapGestureRecognizer 传递参数

Pass Parameter with UITapGestureRecognizer

iphone

xcode

ios

xcode7

swift2

对于Swift 4

按照正确的步骤并根据您的变量、按钮、标签进行更改。它工作正常