仅当字段在 Android 中不为空时才进行电子邮件验证

Email validation only when field is not blank in Android

仅当 EditText 在 Android 中不为空时才验证电子邮件格式。如果该字段为空白,则不应检查验证。在这种情况下,我没有找到任何对我有用的解决方案。

使用此方法检查电子邮件模式是否有效

public static boolean isEmailValid(CharSequence email) {
        return Patterns.EMAIL_ADDRESS.matcher(email).matches();
    }

试试这个代码

final EditText emailEditTxt= (EditText)findViewById(R.id.text); 

String emailStr = emailEditTxt.getText().toString().trim();

if(emailStr!=null)

if(emailStr.length()>=1){

String emailPattern = "[a-zA-Z0-9._-]+@[a-z]+\.+[a-z]+";


if (emailStr .matches(emailPattern))
{
Toast.makeText(getApplicationContext(),"valid email address",Toast.LENGTH_SHORT).show();
}
else 
{
Toast.makeText(getApplicationContext(),"Invalid email address", Toast.LENGTH_SHORT).show();
}
}

验证电子邮件

private boolean validateEmail() {
 if (!edemail.getText().toString().trim().isEmpty()&&!ValidationMethod.emailValidation(edemail.getText().toString()))
    {

        input_layout_email.setError("Invalid Email"); // Your textInput Layout or other set your error on edittext email
        requestFocus(edemail);
        return false;
    }

    else {
        input_layout_email.setErrorEnabled(false);
    }

    return true;
}

   // if you need requestfocus other wise remove
 private void requestFocus(View view) {
    if (view.requestFocus()) {
        getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_VISIBLE);
    }
}

ValidationMethod.java // 放入你的项目

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class ValidationMethod {

    static Matcher m;
    static String emailExpression = "^[\w\.-]+@([\w\-]+\.)+[A-Z]{2,20}$";
    static Pattern emailPattern = Pattern.compile(emailExpression, Pattern.CASE_INSENSITIVE);
    static String passwordExpression ="((?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*\W).{8,20})";
    static Pattern passwordPattern=Pattern.compile(passwordExpression);

    public static boolean emailValidation(String s)
    {
        if( s == null)
        {
            return false; 
        }
        else
        {
            m = emailPattern.matcher(s);
            return m.matches();
        }
    }

    public static boolean passwordValidation(String s)
    {
        if( s == null)
        {
            return false; 
        }
        else
        {
            m = passwordPattern.matcher(s);
            return m.matches();
        }
    }

    public static boolean emailValidation2(String s)
    {
        m = emailPattern.matcher(s);
        return m.matches();
    }
}

试试这个..

boolean flag;
String pass = editText.getText().toString().trim();
if(!pass.equals("")) {
    flag = isEmailValid(pass);
}

public static boolean isEmailValid(CharSequence email) {
    return Patterns.EMAIL_ADDRESS.matcher(email).matches();
}

并使用 flag 值进一步使用

试试这个

<form>
    <lable for="userEmail">Email : </label>
    <input type="email" id="userEmail" placeholder="johndoe@example.com" required="required">
<form>

假设您已经这样声明了 EditText。

编辑文本电子邮件字段;

然后在你的方法中

emailField = (EditText)view.getViewById(R.id.NAME_OF_FIELD_IN_XML);
if(!TextUtils.isBlank(emailField.getText().toString())){
     //validate your email address
}

使用下面的 link 作为电子邮件验证码。


你可以试试这个来验证。

    public boolean Email_validation(String CorpId)
{
    String regExpn =
            "^(([\w-]+\.)+[\w-]+|([a-zA-Z]{1}|[\w-]{2,}))@"
                    +"((([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\.([0-1]?"
                    +"[0-9]{1,2}|25[0-5]|2[0-4][0-9])\."
                    +"([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\.([0-1]?"
                    +"[0-9]{1,2}|25[0-5]|2[0-4][0-9])){1}|"
                    +"([a-zA-Z]+[\w-]+\.)+[a-zA-Z]{2,4})$";

    CharSequence inputStr = CorpId;

    Pattern pattern = Pattern.compile(regExpn, Pattern.CASE_INSENSITIVE);
    Matcher matcher = pattern.matcher(inputStr);

    if(matcher.matches())
        return true;
    else
        return false;
}