当我在导航中传递值时对象不匹配，Xamarin Forms

Question

我尝试从 ListView 页面导航列表视图 Return 来自 Sqlit 的数据当我从 ListView select 时，第一页下面的代码： Xaml代码：

<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
         xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
         x:Class="FirstTestApp.AllTripsPage"
         Title="AllTrips">
<ContentPage.Content>
    <StackLayout Orientation="Vertical">

        <ListView x:Name="TripsList" ItemSelected="TripsList_ItemSelected">
        <ListView.ItemTemplate>
            <DataTemplate>
                <ViewCell>
                    <StackLayout Orientation="Horizontal" Padding="5,5,5,5">
                        <Label Text="{Binding Name}" FontSize="Medium" />
                       </StackLayout>
                </ViewCell>
            </DataTemplate>
        </ListView.ItemTemplate>
    </ListView>
    </StackLayout>
</ContentPage.Content>

C# 函数：

private async void TripsList_ItemSelected(object sender, SelectedItemChangedEventArgs e)
    {
        if (e.SelectedItem == null)
        {
            return;
            //ItemSelected is called on deselection, 
            //which results in SelectedItem being set to null
        }
        var Selected = (Trip)e.SelectedItem;

      await  Navigation.PushAsync(new ShowTrip(Selected));

    }

Page ShowTrip 中的此代码，它查看有关我选择的项目的一些详细信息： xaml代码：

<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
         xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
         x:Class="FirstTestApp.ShowTrip"
         Title="Trip Details">
<ContentView.Content>
    <Label Text="Trip Details" />
        <Label Text="Name" />
        <Label  Text ="{Binding Name}" />
        <Label  Text="Description" />
        <Label  Text ="{Binding Description}"/>
        <Label  Text="Done:" />
    <Label  Text ="{Binding Done}"/>
</ContentView.Content>

C#:

public partial class ShowTrip : ContentPage
{
    Trip SelectTrip;
    public ShowTrip(Trip Selected)
    {

        InitializeComponent();
        SelectTrip = Selected;
        BindingContext = SelectTrip;
    }

}

InitializeComponent()函数出现错误：

 private void InitializeComponent() {
        this.LoadFromXaml(typeof(ShowTrip));///in This Line Exception happened 
    }

错误是："Object does not match target type"

Answer 1

尝试在 ShowTrip 页面上使用 StackLayout 而不是 <ContentView.Content>。

当我在导航中传递值时对象不匹配，Xamarin Forms

Object does not match when i pass value in navigation, Xamarin Forms

navigation

sqlite

cross-platform

xamarin

xamarin.forms