使用相同的代码解析多个字符串

Question

我正在尝试在下方打印 URL 内的所有网球运动员。但是 split 函数只打印一个玩家的名字，尽管其他玩家的名字可以从下面的 split 函数 names1.split('">')[1].split('

import time
import urllib2
from urllib2 import urlopen
import datetime

def Tennis():
    try:
        australianOpen = urllib2.urlopen('http://www.ausopen.com/en_AU/players/profiles.html').read()

        names1 =australianOpen.split('</div><div id="section_A" class="sectionHeading"><div class="men">A</div><div class="women">A</div></div><div class="section"><div class="men">')[1].split('</a></div></div></div></div>')[0]

        for Eachnames in names1 :

            Eachnames = names1.split('">')[1].split('</a><a href="')[0]


            print Eachnames


    except Exception,e:
        print str(e)

Tennis()

Answer 1

只需添加 names1 = names1[names1.find(Eachnames)+len(Eachnames):]

def Tennis():
    try:
        australianOpen = urllib2.urlopen('http://www.ausopen.com/en_AU/players/profiles.html').read()

        #print australianOpen
        names1 =australianOpen.split('</div><div id="section_A" class="sectionHeading"><div class="men">A</div><div class="women">A</div></div><div class="section"><div class="men">')[1].split('</a></div></div></div></div>')[0]

        for Eachnames in names1 :

            Eachnames = names1.split('">')[1].split('</a><a href="')[0]
            names1 = names1[names1.find(Eachnames)+len(Eachnames):]
            if Eachnames.find('<')!= -1:
             Eachnames=Eachnames[:Eachnames.find('<')]


            print Eachnames


    except Exception,e:
        print str(e)

Tennis()

Answer 2

问题与 Eachnames = names1.split('">')[1].split('</a><a href="')[0] 行有关，您在这里所做的是将字符串拆分为子字符串数组，然后 [1] 是 selecting 1:st 元素。由于您在找到第一个名字后没有修改变量 names1，因此您将一遍又一遍地 select 相同的名字。一个简单的修改是

import time
import urllib
import urllib.request
import datetime

def Tennis():
    try:
        australianOpen =     urllib.request.urlopen('http://www.ausopen.com/en_AU/players/profiles.html').read().decode('utf-8')

        names1 =australianOpen.split('</div><div id="section_A" class="sectionHeading"><div     class="men">A</div><div class="women">A</div></div><div class="section"><div class="men">')[1].split('</a></div></div></div></div>')[0]

    the_names = names1.split('">')
    for name in the_names:
       print (name.split('</a><a href="')) 

    except Exception:
        print ("Exception", sys.exc_info()[0])


Tennis()

但是打印输出将是错误的，因为您的搜索条件都是错误的（除非您想要像 half URL adressen et.c 这样的乱码）。我认为一个好的和简单的解决方案是为此使用正则表达式。一个简单的正则表达式来捕获名称，没有特殊字符左右是

the_names = re.findall("\">([A-Za-z]*, [A-Za-z]*)", names1)

使用正则表达式的稍微简化的程序是

import urllib.request
import re

def Tennis():
    try:
        australianOpen = urllib.request.urlopen('http://www.ausopen.com/en_AU/players/profiles.html').read().decode('utf-8')

        names1 =australianOpen.split('</div><div id="section_A" class="sectionHeading"><div class="men">A</div><div class="women">A</div></div><div class="section"><div class="men">')[1].split('</a></div></div></div></div>')[0]
    except Exception:
        print ("Exception")

    the_names = re.findall("\">([A-Za-z]*, [A-Za-z]*)", names1)
    for name in the_names:
        print (name) 

Tennis()

希望这对您有所帮助

使用相同的代码解析多个字符串

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