如何从 HttpResponseMessage(HttpStatusCode, Exception) 检索传递的异常

How can I retrieve passed exception from HttpResponseMessage(HttpStatusCode, Exception)

根据以下网站,您可以将异常参数传递给 HttpResponseMessage.CreateErrorResponse 方法 (https://msdn.microsoft.com/en-us/library/jj127064(v=vs.118).aspx)

我的问题是如何从 CreateErrorResponse 方法创建的 HttpResponseMessage 中检索异常信息。如果没有办法获取异常信息,那么将异常作为输入的方法重载有什么意义?

澄清我不是在寻找什么答案... 我知道我可以在正文内容中传递自定义错误原因 (http://weblogs.asp.net/fredriknormen/asp-net-web-api-exception-handling) 但我真的只是好奇如何使用 HttpRequestMessageExtensions.CreateErrorResponse 方法 (HttpRequestMessage, HttpStatusCode, Exception) 方法重载。

示例 WebAPI 控制器:

Route("location/{locationName}/Databases/{databasename}/ProcedureSession")][LocationSetUp]
public HttpResponseMessage Post([FromBody] ProcedureSessionData procedureSession)
    {
        try
        {
            throw new Exception("test Exception");
        }
        catch (Exception e)
        {
           return Request.CreateErrorResponse(HttpStatusCode.InternalServerError,
             e);
        }
    }

如何获取此代码中的异常:

using (var client = new HttpClient())
  {
    client.BaseAddress = new Uri("http://localhost/");
    client.DefaultRequestHeaders.Accept.Clear();
    client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));

    string api = "testApi/location/here/databases/testDb/ProcedureSession";
    HttpResponseMessage response = client.PostAsJsonAsync(api, newSessionData).Result;
    if (!response.IsSuccessStatusCode)
    {
         //how can i pick up the exception object from here? 
         //Or am I missing the point of this CreateErrorResponse overload?
    }

要从 HttpResponseMessage 获取错误消息,您必须获取 HttpError 对象,如下所示。 HttpError 对象然后包含 ExceptionMessage、ExceptionType 和 StackTrace 信息。

if(!response.IsSuccessStatusCode){
    HttpError error = response.Content.ReadAsAsync<HttpError>().Result;
}

您可以尝试使用

 response.EnsureSuccessStatusCode()

如果未收到成功的响应代码,将引发异常。