Newtonsoft JSON 架构忽略反序列化验证

Newtonsoft JSON Schema Ignore Validations For Deserialize

我关注 JSON & class,

{ "Id": 123, "FirstName": "fName", "LastName": "lName" }

public class Student
{
    public int Id { get; set; }

    [StringLength(4)]
    public string FirstName { get; set; }

    [StringLength(4)]
    public string LastName { get; set; }
} 

我正在尝试反序列化上述 JSON 以创建学生 class 的实例。

var body = //above json as string;

Student model = null;

JSchemaGenerator generator = new JSchemaGenerator();
JSchema schema = generator.Generate(typeof(Student));

using (JsonTextReader reader = new JsonTextReader(new StringReader(body)))
{
    using (JSchemaValidatingReader validatingReader = new JSchemaValidatingReader(reader) { Schema = schema })
    {
        JsonSerializer serializer = new JsonSerializer();
        model = serializer.Deserialize(validatingReader, typeof(Student));
    }
}

这会引发字符串长度验证异常,是否有任何方法可以通过忽略所有数据注释验证来反序列化 JSON?

您可以使用以下代码反序列化您的数据。由于抛出错误,您在序列化之前进行验证。

 var body ="{\"Id\":123,\"FirstName\":\"fNamesdcsdc\",\"LastName\":\"lName\"}";
            using (JsonTextReader reader = new JsonTextReader(new StringReader(body)))
            {
                JsonSerializer serializer = new JsonSerializer();
                var model = serializer.Deserialize(reader, typeof(Student));
            }

另一种方法

            String json="{ \"Id\": 123, \"FirstName\": \"fName\", \"LastName\": \"lName\" }";

            JavaScriptSerializer serializer=new JavaScriptSerializer();
            Student student = serializer.Deserialize<Student>(json);