Specs2 await 不会在范围内失败

Question

当使用 Specs2(v 2.3.13) await 时，我注意到在某些情况下它不会失败。具体来说，我观察到如果 "await" 在范围内超时，那么它不会失败。

"Awaiting a failed future should fail" in {
  Future.failed(throw new Exception()).map(_ => success).await // Fails Correctly
}
"Awaiting a timed out future should fail" in {
  Future(Thread.sleep(5000)).map(_ => success).await // Fails Correctly
}
"Awaiting a failed scope should fail" in new Scope {
  failure // Fails Correctly
}
"Awaiting a failed future in a scope should fail" in new Scope {
  Future.failed(throw new Exception()).map(_ => success).await // Fails Correctly
}
"Awaiting a timed out future in a scope should fail" in new Scope {
  Future(Thread.sleep(5000)).map(_ => success).await  // DOES NOT FAIL
}

是我误解了用法，还是这是一个错误？

Answer 1

隐含在 Future[T] 上的 .await 只会创建一个 Result，如果超时，它将失败。但是不会抛出任何异常，因此结果不会逃脱 Scope 特征。

要解决此问题，您需要使用 Matchers 并在 Future[T]:

中指定您对类型 T 的期望值

Future(Thread.sleep(5000)).map(_ => 1) must be_==(1).await

这将正确显示

[info] x Awaiting a timed out future in a scope should fail
[error]  Timeout after 1 second (TestSpec.scala:35)

Specs2 await 不会在范围内失败

Specs2 await doesn't fail inside of a Scope

specs2