按值删除 jsonb 数组元素

Question

我确实弄清楚了如何从数组中删除单个记录的值，但如何为其中的许多记录执行此操作。问题在于我如何使用子查询。因为它必须 return 只有单个元素。可能是我的做法不对。


    给定输入：'{attributes:['is_new', 'is_old']}'
    预期结果 '{attributes: ['is_old']}' #remove 'is_new' from jsonb array


    真实例子：
    # 库存 |特性
    # ------+--------------------------------
    # nu3_1 | { +
    # | "name": "silly_hodgkin", +
    # | "type": "food", +
    # | "attributes"：[+
    # | "is_gluten_free", +
    # | "is_lactose_free", +
    # | "is_new" +
    # | ] +
    # | }


#删除单个数组元素的查询：

SELECT c.sku, jsonb_agg(el) 来自
catalog c JOIN (select sku, jsonb_array_elements_text(properties->'attributes') as el from catalog) c2 ON c.sku=c2.sku 其中 el 'is_new'
分组 c.sku；

#更新删除单个记录中的单个数组元素的查询

更新目录 SET properties=jsonb_set(properties, '{attributes}', (
    SELECT jsonb_agg(el) 来自
    目录 c JOIN (select sku, jsonb_array_elements_text(properties->'attributes') as el from catalog) c2 ON c.sku=c2.sku
    其中 el 'is_new' 和 c.sku='nu3_1'
    分组 c.sku
    )
) 哪里 sku='nu3_1';

问题又来了。如何根据多个数据库记录的值删除 jsonb 数组元素？

Answer 1

所以，我相信您正在寻找的 QRY 是：

with q as (
  select distinct sku, jsonb_set(properties,'{attributes}',jsonb_agg(el) over (partition by sku),false) new_properties
  from (
    select 
      sku, jsonb_array_elements_text(properties->'attributes') as el, properties
    from catalog
  ) p
  where el != 'is_new'
)
update catalog set properties = q.new_properties from q where catalog.sku = q.sku
;

请注意，我假设您的 sku 至少是 UK!

Answer 2

您的解决方案有效 + 您向我指出了一些新的东西，例如 window 函数，并为我提供了替代解决方案的想法：

WITH q as (
  SELECT c.sku as sku,  jsonb_set(properties, '{attributes}', jsonb_agg(el)) as new_properties
    FROM catalog c JOIN (select sku, jsonb_array_elements_text(properties->'attributes') as el from catalog) c2 ON c.sku=c2.sku where el != 'is_new'
    GROUP BY c.sku
)
UPDATE catalog SET properties=q.new_properties FROM q WHERE catalog.sku=q.sku;

Answer 3

使用jsonb_set() and the delete operator -:

update catalog
set properties = 
    jsonb_set(properties, '{attributes}', (properties->'attributes') - 'is_new');

在db<>fiddle.

中测试

Answer 4

根据documentation:

json_build_object ( VARIADIC "any" ) → json

jsonb_build_object ( VARIADIC "any" ) → jsonb

Builds a JSON object out of a variadic argument list. By convention, the argument list consists of alternating keys and values. Key arguments are coerced to text; value arguments are converted as per to_json or to_jsonb.

json_build_object('foo', 1, 2, row(3,'bar')) → {"foo" : 1, "2" : {"f1":3,"f2":"bar"}}

update catalog
set properties = properties - 'attributes' || jsonb_build_object('attributes','[is_gluten_free,is_lactose_free,is_new]')
where properties ? 'attributes' 
returning *;

现在您可以替换键，也可以替换值。只需确保 attributes 为顶级键即可。

按值删除 jsonb 数组元素

Remove jsonb array element by value

arrays

postgresql

json

jsonb