休眠一对一 XML 映射不插入外键
Hibernate One to One XML mapping not inserting foreign key
我有这些 类:
class Parent {
private int parentId;
private Child child;
}
class Child {
private int childId;
private Parent parent;
}
以及以下 XML 映射:
<hibernate-mapping>
<class name="com.package.Parent" table="PARENT">
<id name="id" type="int" column="parent_col_id"/>
<one-to-one name="child" class="com.package.Child">
</class>
</hibernate-mapping>
<hibernate-mapping>
<class name="com.package.Child" table="Child">
<id name="id" type="int" column="child_col_id"/>
<one-to-one name="Parent" class="com.package.Parent">
</class>
</hibernate-mapping>
MySQL 数据库看起来像这样:
ParentDB
parent_col_id INT(11) PK NN AI
ChildDB
child_col_id INT(11) PK NN AI
name VARCHAR(45) (none checked)
parent_id INT(11) (none checked)
现在让我们尝试更新它们!
Session hSession = sessionService.openSession();
Parent parent = hSession.get(Parent.class, parentId);
Child child = new Child();
child.setName = "CooCoo";
parent.setChild(child);
childRepo.insert(child, hSession);
hSession.close();
现在,问题是 child 被插入到数据库中,但外键没有!这让我的children被抛弃了!请保存我的 children :(
我做错了什么?
我尝试将外键列移动到 parent 一侧。仍然没有。Hibernate 如何知道 parent_id 或 child_id 列是外键 ID?
我改成下面的代码后就成功了:
已将 XML 映射更改为:
<hibernate-mapping>
<class name="com.package.Parent" table="PARENT">
<id name="id" type="int" column="parent_col_id"/>
<one-to-one name="child" class="com.package.Child" cascade="all"/>
</class>
</hibernate-mapping>
<hibernate-mapping>
<class name="com.package.Child" table="Child">
<id name="id" type="int" column="child_col_id">
<generator class="foreign">
<param name="property">parent</param>
</generator>
</id>
<one-to-one name="Parent" class="com.package.Parent">
</class>
</hibernate-mapping>
已将 java 代码更改为:
Session hSession = sessionService.openSession();
Parent parent = hSession.get(Parent.class, parentId);
Child child = new Child();
child.setName = "CooCoo";
parent.setChild(child);
child.setParent(parent);
parentRepo.update(parent, hSession);
hSession.close();
在 MySQL 中,删除了 parent_id 列,因为外部 ID 被设置为主键 ID。
希望这对某人有所帮助!
我有这些 类:
class Parent {
private int parentId;
private Child child;
}
class Child {
private int childId;
private Parent parent;
}
以及以下 XML 映射:
<hibernate-mapping>
<class name="com.package.Parent" table="PARENT">
<id name="id" type="int" column="parent_col_id"/>
<one-to-one name="child" class="com.package.Child">
</class>
</hibernate-mapping>
<hibernate-mapping>
<class name="com.package.Child" table="Child">
<id name="id" type="int" column="child_col_id"/>
<one-to-one name="Parent" class="com.package.Parent">
</class>
</hibernate-mapping>
MySQL 数据库看起来像这样:
ParentDB
parent_col_id INT(11) PK NN AI
ChildDB
child_col_id INT(11) PK NN AI
name VARCHAR(45) (none checked)
parent_id INT(11) (none checked)
现在让我们尝试更新它们!
Session hSession = sessionService.openSession();
Parent parent = hSession.get(Parent.class, parentId);
Child child = new Child();
child.setName = "CooCoo";
parent.setChild(child);
childRepo.insert(child, hSession);
hSession.close();
现在,问题是 child 被插入到数据库中,但外键没有!这让我的children被抛弃了!请保存我的 children :( 我做错了什么?
我尝试将外键列移动到 parent 一侧。仍然没有。Hibernate 如何知道 parent_id 或 child_id 列是外键 ID?
我改成下面的代码后就成功了:
已将 XML 映射更改为:
<hibernate-mapping>
<class name="com.package.Parent" table="PARENT">
<id name="id" type="int" column="parent_col_id"/>
<one-to-one name="child" class="com.package.Child" cascade="all"/>
</class>
</hibernate-mapping>
<hibernate-mapping>
<class name="com.package.Child" table="Child">
<id name="id" type="int" column="child_col_id">
<generator class="foreign">
<param name="property">parent</param>
</generator>
</id>
<one-to-one name="Parent" class="com.package.Parent">
</class>
</hibernate-mapping>
已将 java 代码更改为:
Session hSession = sessionService.openSession();
Parent parent = hSession.get(Parent.class, parentId);
Child child = new Child();
child.setName = "CooCoo";
parent.setChild(child);
child.setParent(parent);
parentRepo.update(parent, hSession);
hSession.close();
在 MySQL 中,删除了 parent_id 列,因为外部 ID 被设置为主键 ID。
希望这对某人有所帮助!