SQL 查询：每个列值都是基于临时 table 上的不同过滤器的聚合

Question

我想根据结果 table 中每一列的特定条件从 table 中获取行数。 table 本身是临时的 table.

下面的查询是我想要完成的，但我不知道用什么语法来实现它：

WITH table1 as( a huge inner joins between different tables)

SELECT *
FROM (
    (
        SELECT COUNT(*) 
        FROM table1
        WHERE 
            column1 = 'value1' AND column2 > 0
    ) AS Count1,
    (
        SELECT COUNT(*) 
        FROM table1
        WHERE 
            column1 = 'value1' AND column2 = 0
    )AS Count2,
    (
        SELECT COUNT(*) 
        FROM table1
        WHERE 
            column1 = 'value2' AND column2 > 0
    )AS Count3,
    (
        SELECT COUNT(*) 
        FROM table1
        WHERE 
            column1 = 'value2' AND column2 = 0
    ) AS Count4
) CountSummary

这不是正确的语法，但我不确定如何在 sql 服务器中实现这个概念。

如果我使查询的第二部分等于：select * from table1

，这就是我目前遇到的错误

Msg 252, Level 16, State 1, Line 1
Recursive common table expression 'table1' does not contain a top-level UNION ALL operator.

庞大的inner join查询可以运行单独无误

--------------------更新------------------------ -

递归错误是由于命名 'table1' 与内部连接查询部分中的 table 相同，我摆脱了它，错误消失了。然后我尝试了答案，它们都有效。

Answer 1

也许是这样的：-

select
    sum(case when column1 = 'value1' and column2 > 0 then 1 else 0 end) as Count1,
    sum(case when column1 = 'value1' and column2 = 0 then 1 else 0 end) as Count2,
    sum(case when column1 = 'value2' and column2 > 0 then 1 else 0 end) as Count3,
    sum(case when column1 = 'value2' and column2 = 0 then 1 else 0 end) as Count4
from table1

Answer 2

这样做：

WITH table1 as( a huge inner joins between different tables)

SELECT * FROM 
    (
        SELECT COUNT(*) AS Count1
        FROM table1
        WHERE 
            column1 = 'value1' AND column2 > 0
    ) AS Count1,
    (
        SELECT COUNT(*) AS Count2
        FROM table1
        WHERE 
            column1 = 'value1' AND column2 = 0
    ) AS Count2

SQL 查询：每个列值都是基于临时 table 上的不同过滤器的聚合

SQL Query: each column value is an aggergation based on a different filter on a temporary table

sql

sql-server

syntax

aggregation