将 lodash _.uniqBy() 转换为原生 javascript

Question

在这个片段中，我卡在了 _.uniqBy(array,iteratee)，这个

iteratee可以同时是函数或字符串
在什么地方放置检查唯一性的条件属性因为 itratee 函数可以是任何东西

var sourceArray = [ { id: 1, name: 'bob' },
  { id: 1, name: 'bill' },
  { id: 1, name: 'bill' } ,
  {id: 2,name: 'silly'},
  {id: 2,name: 'billy'}]

function uniqBy (inputArray, callback) {
  return inputArray.filter(callback)
}
var inputFunc = function (item) {
  return item.name
}

// var destArray = _.uniqBy(sourceArray,'name')

var destArray = uniqBy(sourceArray, inputFunc)
console.log('destArray', destArray)

我们将不胜感激。

Answer 1

您可以使用按名称排序的排序和基于邻域比较的过滤器，如下所示：

var sourceArray = [ { id: 1, name: 'bob' },
  { id: 1, name: 'bill' },
  { id: 1, name: 'bill' } ,
  {id: 2,name: 'silly'},
  {id: 2,name: 'billy'}]

var uniqBy = (inputArray, callback) => inputArray.sort((a,b) => callback(a) > callback(b))
.filter((x,i,arr) => i === arr.length -1 ? true : callback(x) !== callback(arr[i+1]));
var inputFunc = item => item.name;


var destArray = uniqBy(sourceArray, inputFunc)
console.log('destArray', destArray)

Answer 2

ES6 uniqBy 使用 Map 复杂度为 O(n):

const uniqBy = (arr, predicate) => {
  const cb = typeof predicate === 'function' ? predicate : (o) => o[predicate];
  
  return [...arr.reduce((map, item) => {
    const key = (item === null || item === undefined) ? 
      item : cb(item);
    
    map.has(key) || map.set(key, item);
    
    return map;
  }, new Map()).values()];
};

const sourceArray = [ 
  { id: 1, name: 'bob' },
  { id: 1, name: 'bill' },
  null,
  { id: 1, name: 'bill' } ,
  { id: 2,name: 'silly'},
  { id: 2,name: 'billy'},
  null,
  undefined
];

console.log('id string: ', uniqBy(sourceArray, 'id'));

console.log('name func: ', uniqBy(sourceArray, (o) => o.name));

Answer 3

我是运行我在 Create React App 中通过 Webpack 编写的代码，它必须使用 polyfill 来传播使用切片。这是我所做的，@oridori 答案的变体：

const uniqBy = (arr: any[], predicate: (item: any) => string) => {
  const cb = typeof predicate === 'function' ? predicate : (o) => o[predicate];
  const result = [];
  const map = new Map();

  arr.forEach((item) => {
    const key = (item === null || item === undefined) ? item : cb(item);

    if (!map.has(key)) {
      map.set(key, item);
      result.push(item);
    }
  });

  return result;
};

Answer 4

重构并删除了@ori-drori 的解决方案

undefined
null
混合数组中的额外数字
return [] 如果第一个参数不是 Array

const uniqBy = (arr, predicate) => {
  if (!Array.isArray(arr)) { return []; }

  const cb = typeof predicate === 'function' ? predicate : (o) => o[predicate];

  const pickedObjects = arr
    .filter(item => item)
    .reduce((map, item) => {
        const key = cb(item);

        if (!key) { return map; }

        return map.has(key) ? map : map.set(key, item);
    }, new Map())
    .values();
 
  return [...pickedObjects];
};

const a = [ 
  12,
  undefined,
  { id: 1, name: 'bob' },
  null,
  { id: 1, name: 'bill' },
  null,
  undefined
];

const b = [ 
  12,
  { id: 1, name: 'bob' },
  { id: 1, name: 'bill' },
];

uniqBy(a, 'name');
uniqBy(b, Math.floor);
uniqBy([2.1, 1.2, 2.3], Math.floor);

将 lodash _.uniqBy() 转换为原生 javascript

Converting lodash _.uniqBy() to native javascript

javascript

arrays

distinct-values

lodash