如何使用 JUnit 测试 Spring 中的 ConfigurationProperties？

Question

我有一个 ConfigurationProperties class 并想用 junit 测试它。但是对象总是null。以下代码中可能缺少什么？

@EnableAutoConfiguration
@ComponentScan
@EnableConfigurationProperties(MyProperties.class)
public class AppConfig {

}

@Service
public class MyService {
    @Autowired
    private MyProperties props;

    public void run() {
        props.getName();
    }
}

@Component
@ConfigurationProperties(prefix = "my")
public class MyProperties {
    private String name;
    //getter,setter
}

application.properties:

my.name=test

测试：

@Configuration
@ComponentScan(basePackageClasses = {MyService.class,  MyProperties.class},
            includeFilters = @ComponentScan.Filter(value = {MyService.class,  MyProperties.class},
            type = FilterType.ASSIGNABLE_TYPE),
            lazyInit = true
)
@PropertySources(
        @PropertySource("application.properties")
    )
class AppTest {
    @Bean
    public static PropertySourcesPlaceholderConfigurer propertiesResolver() {
        return new PropertySourcesPlaceholderConfigurer();
    }
}

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(classes = ApplicationConfigTest.class)
public class MyTest extends AbstractJUnit4SpringContextTests {
    @Autowired
    private MyService service;

    @Test
    public void testService() {
        service.run();
    }
}

Answer 1

以下将为您加载：

@ContextConfiguration(classes = Application.class, initializers = ConfigFileApplicationContextInitializer.class)

如何使用 JUnit 测试 Spring 中的 ConfigurationProperties？

How to test ConfigurationProperties in Spring with JUnit?

java

junit

spring

spring-test