实体子项上 where 条件的 Linq 表达式
Linq expression for where condition on entity child
你好,
如何通过 linq 表达式构建以下语句以便翻译成 sql?
builder.Where(e => e.SomeChild.Name.ToLower() == "something");
builder
是一个 DbContext。当我直接调用它时,它被正确解释为这样
select ... from someTable
inner join childTable on ...
where LOWER(childTable.Name) = @someParam
所以我这样构建 where 条件:
private readonly Expression<Func<TEntity, TProperty>> _property;
private Expression<Func<TEntity, bool>> insensitiveEqualityPredicate(string formula)
{
var parameter = Expression.Parameter(typeof(TEntity));
var property = (PropertyInfo)((MemberExpression)_property.Body).Member;
var propertyParameter = Expression.Parameter(property.DeclaringType);
var lowerExpression = Expression.Call(
Expression.Invoke(_property, propertyParameter),
typeof(string).GetMethods().Where(m => m.Name == "ToLower" && m.GetParameters().ToList().Count == 0).FirstOrDefault()
);
return Expression.Lambda<Func<TEntity, bool>>(
Expression.Equal(
lowerExpression,
Expression.Constant(formula.ToLower(), typeof(string))
),
parameter
);
}
它很有魅力:
_property = e => e.Name;
...
builder.Where(insensitiveEqualityPredicate("whatever"));
但不适用于儿童条件:
_property = e => e.SomeChild.Name;
...
builder.Where(insensitiveEqualityPredicate("whatever"));
因为:
The LINQ expression 'Param_0.Name.Equal("whatever")' could not be translated and will be evaluated locally.
正确的做法是什么?
提前致谢。
据我了解,您有一个类型为 Expression<Func<TEntity, TProperty>>
的字段 _property
(在这种特殊情况下,它实际上是 Expression<Func<TEntity, string>>
),它是用 lambda 表达式初始化的,例如 e => e.Name
, e => e.SomeChild.Name
等等
为了构建所需的谓词,您可以重复使用 _property
表达式参数并使用 Body
属性 作为新表达式的基础:
private readonly Expression<Func<TEntity, TProperty>> _property;
private Expression<Func<TEntity, bool>> insensitiveEqualityPredicate(string formula)
{
return Expression.Lambda<Func<TEntity, bool>>(
Expression.Equal(
Expression.Call(_property.Body, "ToLower", Type.EmptyTypes),
Expression.Constant(formula.ToLower(), typeof(string))
),
_property.Parameters
);
}
你好,
如何通过 linq 表达式构建以下语句以便翻译成 sql?
builder.Where(e => e.SomeChild.Name.ToLower() == "something");
builder
是一个 DbContext。当我直接调用它时,它被正确解释为这样
select ... from someTable
inner join childTable on ...
where LOWER(childTable.Name) = @someParam
所以我这样构建 where 条件:
private readonly Expression<Func<TEntity, TProperty>> _property;
private Expression<Func<TEntity, bool>> insensitiveEqualityPredicate(string formula)
{
var parameter = Expression.Parameter(typeof(TEntity));
var property = (PropertyInfo)((MemberExpression)_property.Body).Member;
var propertyParameter = Expression.Parameter(property.DeclaringType);
var lowerExpression = Expression.Call(
Expression.Invoke(_property, propertyParameter),
typeof(string).GetMethods().Where(m => m.Name == "ToLower" && m.GetParameters().ToList().Count == 0).FirstOrDefault()
);
return Expression.Lambda<Func<TEntity, bool>>(
Expression.Equal(
lowerExpression,
Expression.Constant(formula.ToLower(), typeof(string))
),
parameter
);
}
它很有魅力:
_property = e => e.Name;
...
builder.Where(insensitiveEqualityPredicate("whatever"));
但不适用于儿童条件:
_property = e => e.SomeChild.Name;
...
builder.Where(insensitiveEqualityPredicate("whatever"));
因为:
The LINQ expression 'Param_0.Name.Equal("whatever")' could not be translated and will be evaluated locally.
正确的做法是什么?
提前致谢。
据我了解,您有一个类型为 Expression<Func<TEntity, TProperty>>
的字段 _property
(在这种特殊情况下,它实际上是 Expression<Func<TEntity, string>>
),它是用 lambda 表达式初始化的,例如 e => e.Name
, e => e.SomeChild.Name
等等
为了构建所需的谓词,您可以重复使用 _property
表达式参数并使用 Body
属性 作为新表达式的基础:
private readonly Expression<Func<TEntity, TProperty>> _property;
private Expression<Func<TEntity, bool>> insensitiveEqualityPredicate(string formula)
{
return Expression.Lambda<Func<TEntity, bool>>(
Expression.Equal(
Expression.Call(_property.Body, "ToLower", Type.EmptyTypes),
Expression.Constant(formula.ToLower(), typeof(string))
),
_property.Parameters
);
}