路径规范中的两个点如何工作

Question

在这个例子中

#include <iostream>
#include <experimental/filesystem>
namespace fs = std::experimental::filesystem;
int main()
{
    fs::path p = fs::path("..") / ".." / "AppData";//What is it?
    std::cout << "Current path is " << fs::current_path() << '\n'
              << "Canonical path for " << p << " is " << fs::canonical(p) << '\n';
}

什么是 ".."，它是如何工作的？

Answer 1

.. 是父目录，如果您在 /home/user/kat 并转到 .. 您将在 /home/user.

例如这样的代码：

fs::path parentPath = fs::current_path() / "..";
std::cout << parentPath << " → " << fs::canonical(parentPath) << std::endl;

将产生此输出（在我的 PC 上）：

"/home/kamil/Pulpit/build/.." → "/home/kamil/Pulpit"

路径规范中的两个点如何工作

How do two dots in work in path specifications

c++

filesystems

boost