将列反透视为行（oracle）

Question

很像原来的 SO Pivoting rows into columns dynamically in Oracle

但我想反其道而行之

我怎样才能得到

 ID       NAME    AGE    GENDER  STATUS
----     -----   -----  ------  --------
  1      Bob      30     male 
  2      Susan                   married

进入这个

ID       K       V
----     -----   -----
  1      name    Bob
  1      age     30
  1      gender  male
  2      name    Susan
  2      status  married

Answer 1

您正在寻找 unpivot.

select * from t 
unpivot (
          v for k in ("NAME","AGE","GENDER","STATUS")
        ) u

如果年龄列是整数，则类型可能不匹配。在这种情况下，在取消旋转之前将其转换为字符。

select *
from (select id,name,to_char(age) age,gender,status from t) t 
unpivot (
         v for k in ("NAME","AGE","GENDER","STATUS")
        ) u

将列反透视为行（oracle）

Unpivot columns into rows (oracle)

sql

oracle

unpivot

oracle11g