将 json 解析为 html 模板
Parse json into html template
我 select 数据库中的一行有一些 json 内容
我的函数到 select 行
@route('/list')
def list():
c = conn.cursor()
c.execute("SELECT content FROM pages WHERE URL = 'blob.com'")
select = c.fetchall()
return template('views/list.tpl', rows=select)
第 'content' 行的结果是:
{ "ruleGroups": {
"SPEED": { "score": 97 }
},
"pageStats": { "numberResources": 3,
"numberHosts": 2,
"totalRequestBytes": "500",
"imageResponseBytes": "3148",
"otherResponseBytes": "3838"
},
"screenshot": { "mime_type": "image/jpeg",
"data": "imgcontent",
"width": 320,
"height": 240,
}
}
我想在 list.tpl 中显示 json "score"、"numberResources" 和 "numberHosts"。
我应该如何在 list.tpl 中进行?
在您的模板中执行以下操作:
% for row in rows:
% for key, value in row.iteritems():
%if key == 'ruleGroups':
<p>SCORE: {{value['SPEED']['score']}}</p>
%elif key == 'pageStats':
<p>Number of resources: {{value['numberResources']}}</p>
<p>Number of hosts: {{value['numberHosts']}}</p>
%end
%end
%end
我 select 数据库中的一行有一些 json 内容
我的函数到 select 行
@route('/list')
def list():
c = conn.cursor()
c.execute("SELECT content FROM pages WHERE URL = 'blob.com'")
select = c.fetchall()
return template('views/list.tpl', rows=select)
第 'content' 行的结果是:
{ "ruleGroups": {
"SPEED": { "score": 97 }
},
"pageStats": { "numberResources": 3,
"numberHosts": 2,
"totalRequestBytes": "500",
"imageResponseBytes": "3148",
"otherResponseBytes": "3838"
},
"screenshot": { "mime_type": "image/jpeg",
"data": "imgcontent",
"width": 320,
"height": 240,
}
}
我想在 list.tpl 中显示 json "score"、"numberResources" 和 "numberHosts"。
我应该如何在 list.tpl 中进行?
在您的模板中执行以下操作:
% for row in rows:
% for key, value in row.iteritems():
%if key == 'ruleGroups':
<p>SCORE: {{value['SPEED']['score']}}</p>
%elif key == 'pageStats':
<p>Number of resources: {{value['numberResources']}}</p>
<p>Number of hosts: {{value['numberHosts']}}</p>
%end
%end
%end