SQL：列出用户及其 phone 号码和电子邮件地址

Question

我想在 PostgreSQL 中进行查询，其中列出我的用户及其电子邮件地址和 phone 数字（以逗号分隔），如下所示：

| user1 | email1@mail.com, email2@mail.com | +3612123123, +3623234234 |

表格是：

user - stores the user's data

user_email - stores the user's email addresses

user_phone - stores the user's phone numbers

我试过 obvius:

SELECT user.id, user.name
(
  SELECT array_agg(user_email.email)
  FROM user_email
  WHERE user_email.user_id = user.id
) AS EmailAddresses,
(
  SELECT array_agg(user_phone.phone)
  FROM user_phone
  WHERE user_phone.user_id = user.id
) AS PhoneNumbers
FROM user
ORDER BY user.id

但这会导致荒谬的查询时间（34 秒）。比我试过：

SELECT user.id, user.name, array_agg(user_email.email), array_agg(user_phone.phone)
FROM user
LEFT JOIN user_email ON user_email.user_id = user.id
LEFT JOIN user_phone ON user_phone.user_id = user.id
GROUP BY user.id
ORDER BY user.id

这会产生非常好的查询时间（大约 100 毫秒）。但通过这种方式，它列出了 phone 号码和电子邮件地址的每个组合。因此，如果我有 3 个电子邮件地址和 3 个 phone 号码，那么它会列出 9 个电子邮件地址（每个地址的三倍）和 9 个 phone 号码。

有没有一种有效的方法来做我想做的事？

Answer 1

或者DISTINCT

SELECT DISTINCT user.id, user.name, array_agg(user_email.email), array_agg(user_phone.phone)
FROM user
LEFT JOIN user_email ON user_email.user_id = user.id
LEFT JOIN user_phone ON user_phone.user_id = user.id
GROUP BY user.id
ORDER BY user.id

或INNER加入

SELECT user.id, user.name, array_agg(user_email.email), array_agg(user_phone.phone)
FROM user
INNER JOIN user_email ON user_email.user_id = user.id
INNER JOIN user_phone ON user_phone.user_id = user.id
GROUP BY user.id
ORDER BY user.id

或两者兼而有之

SELECT DISTINCT user.id, user.name, array_agg(user_email.email), array_agg(user_phone.phone)
FROM user
INNER JOIN user_email ON user_email.user_id = user.id
INNER JOIN user_phone ON user_phone.user_id = user.id
GROUP BY user.id
ORDER BY user.id

Answer 2

DISTINCT 也可以在 aggregate expressions 中使用：

SELECT "user".id, name, array_agg(DISTINCT email) emails, array_agg(DISTINCT phone) phones
FROM "user"
LEFT JOIN user_email ON user_email.user_id = "user".id
LEFT JOIN user_phone ON user_phone.user_id = "user".id
GROUP BY "user".id
ORDER BY "user".id;

注意：如果您只需要逗号分隔的列表，您可能需要使用 string_agg() 而不是 array_agg()。

SQLFiddle

SQL：列出用户及其 phone 号码和电子邮件地址

SQL: list users with their phone numbers and email addresses

sql

postgresql