将日期时间向下舍入到前一小时

Question

如何将日期时间向下舍入到前一小时？例如：

print datetime.now().replace(microsecond=0)
>> 2017-01-11 13:26:12.0

四舍五入到前一小时：2017-01-11 12:00:00.0

Answer 1

如果您想四舍五入到小时，您只需将 microsecond、second 和 minute 替换为零即可：

print(datetime.now().replace(microsecond=0, second=0, minute=0))

如果您想向下舍入到前小时（如示例 2017-01-11 13:26:12.0 至 2017-01-11 12:00:00.0 中所述），请替换 microsecond , second 和 minute 用零，然后减去一小时：

from datetime import datetime, timedelta

print(datetime.now().replace(microsecond=0, second=0, minute=0) - timedelta(hours=1))

shell中的示例：

$ python3
Python 3.5.2 (default, Nov 17 2016, 17:05:23) 
[GCC 5.4.0 20160609] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> from datetime import datetime, timedelta
>>> print(datetime.now().replace(microsecond=0, second=0, minute=0) - timedelta(hours=1))
2017-01-11 16:00:00

Answer 2

from datetime import datetime, timedelta

n = datetime.now() - timedelta(hours=1)
new_date = datetime(year=n.year, month=n.month, day=n.day, hour=n.hour)

Answer 3

from datetime import datetime
import pandas as pd

currTime = datetime.now()

time = pd.to_datetime(currTime).floor('H')

将日期时间向下舍入到前一小时

Round down datetime to previous hour

python

datetime

rounding